Chemical Bonding and Molecular Structure Test 24

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Chemical Bonding and Molecular Structure Test 24

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Weekly Quiz Competition

Question 1
1 / -0

Which cholrine atom is more electronegative in the following ?

A
$$ CH_3CI $$

B
$$ CH_3CH_2CI $$

C
$$ (CH_3)_2CHCI $$

D
$$CH_3 CH_2 - \underset{Cl}{\underset{|}{C}} - (CH_3)_2$$

Solution

$$3^0$$ carbon is more electronegative
hence option D is correct because of the halide attach carbon is $$3^0$$
Question 2
1 / -0

In which different forms does nitrogen exist in compounds?
$$1$$. bonded by a triple covalent bond
$$2$$. as part of a cation
$$3$$ in a oxidation state of $$+5$$.

A
$$1, 2$$ and $$3$$ are correct

B
$$1$$ and $$2$$ only are correct

C
$$2$$ and $$3$$ only are correct

D
$$1$$ only is correct

Solution

$$1$$. Di-Nitrogen is bonded by a triple covalent bond
$$2$$. Nitrogen act as part of a cation as shown in the figure.
$$3$$ Nitrogen can have oxidation state of $$+5 $$ in $$N_2O_5$$.
Question 3
1 / -0

The hybrid states of carbon atoms in $${(\overset{B}CN)_4}\overset{A}{C_2}$$ are A and B and number of $$\pi$$ bonds in compound is C. Then?

A
$$A=sp, B=sp^2$$ and $$C=9$$

B
$$A=sp^2, B=sp$$, and $$C=9$$

C
$$A=sp^3, B=sp$$ and $$C=9$$

D
$$A=sp^2, B=sp^2$$ and $$C=9$$

Solution

From the above shown strucutre we can observe that-
The hybrid state B is $$sp$$ and that of A is $$sp^2$$ and the total no. of $$\pi$$ bond, $$C=9$$.

Option B is correct.
Question 4
1 / -0

Find the incorrect match.

A
$$ Al_2Cl_6$$ : $$3C-4e$$ bond is present

B
$$ Al_2(CH_3)_6$$ : All carbon atoms are $$ sp^3 $$ - hybridized

C
$$ I_2Cl_6 $$ : Nonplanar

D
$$ Al_2Br_6 $$ : Nonpolar

Solution

Square planar geometry for individual $$I$$-atoms, and to minimize the repulsion of lone pair on $$I$$-atoms overall molecule must be planar.
Question 5
1 / -0

Conjugated double bond is present in_______

A
Propylene

B
Isobutylene

C
Butylene

D
Butadiene

Solution

Butadiene $$CH_{2}=CH-CH=CH_{2}$$

A single bond separated by two double bonds is known as conjugated double bond.
Question 6
1 / -0

Order of arrangement of the following compounds with increasing dipole moment is?

A
(i) $$<$$ (iv) $$<$$ (ii) $$<$$ (iii)

B
(iv) $$<$$ (i) $$<$$ (ii) $$<$$ (iii)

C
(iv) $$<$$ (i) $$<$$ (iii) $$<$$ (ii)

D
(iv) $$<$$ (ii) $$<$$ (i) $$<$$ (iii)

Solution

Toluene has higher dipole moment than p-chlorobenzene and lower than o-chlorobenzene and m-chlorobenzene.

Hence the correct order is-
(iv) < (i) < (ii) < (iii)
Question 7
1 / -0

Among the following molecules in increasing order of $$\sigma$$ to $$\pi$$ bond ratio.

A
$$2 < 3 < 4 < 1$$

B
$$2 < 4 < 3 < 1$$

C
$$3 < 2 < 1 < 4$$

D
$$2 < 3 < 1 < 4$$

Solution

The correct order is-
3<2<1<4
Question 8
1 / -0

In the group the carbonyl carbon is joined to other atoms by:

A
two sigma and one pi bond

B
three sigma and one pi bond

C
two sigma and two pi bonds

D
three sigma and two pi bonds

Solution

in given group the carbonyl carbon is attached to other atom by three sigma and one pi bonds. by sigma bonds two with carbon of alkyl group and one with oxygen. and by pi bond it is joined with Oxygen atom.
Question 9
1 / -0

A compound with molecular formula $$C_{4}H_{6}$$ may contain.

A
two double bond

B
Two double bonds or a triple bond

C
A triple bond

D
All single bonds

Solution
Question 10
1 / -0

Which of the following does not contain three electron bond?

A
$$ ClO_2 $$

B
$$ CO_2 $$

C
$$ O_2^-$$

D
$$ NO $$

Solution

$$ClO_{2},O_{2}^{-},NO$$ all have three electron bonds. But $$CO_{2}$$ has two carbon-oxygen double bonds in the regular structure. So the correct option is B.