Chemical Bonding and Molecular Structure Test 42

Result

Chemical Bonding and Molecular Structure Test 42

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Weekly Quiz Competition

Question 1
1 / -0

Dipole moment of $$H_2O$$ is $$1.84 D$$.If the bond angle is $$105^o$$ and $$O-H$$ bond length is $$0.94 AA $$,what is the magnitude of charge on the atom in water molecules?

A
$$2\times10^{-10}$$ esu

B
$$3.28\times10^{-10}$$ esu

C
$$3.22\times10^{-10}$$ esu

D
$$1.602\times10^{-19} C$$

Solution
Question 2
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The bonds present in borazole are

A
9 $$sigma$$, 6 $$pi$$

B
12 $$sigma$$, 3 $$pi$$

C
6 $$sigma$$, 9 $$pi$$

D
15 $$sigma$$ only

Solution
Question 3
1 / -0

The molecule which have zero dipole moment is

A
$${CH}_{2}{Cl}_{2}$$

B
$${BF}_{3}$$

C
$${NF}_{3}$$

D
$${IF}_{3}$$

Solution
Question 4
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Dative bond is not present in ?

A
$$NH_{4}^{+}$$

B
$$N_{2}O$$

C
$$BCl_{3}$$

D
$$B_{3}N_{3}H_{6}$$

Solution
Question 5
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The correct order $$C-O)$$ bond length among $$CO,{ CO }_{ 3 }^{ -2 },{ CO }_{ 2 }$$ is

A
$$CO<{ CO }_{ 2 }<{ CO }_{ 3 }^{ -2 }$$

B
$${ CO }_{ 2 }<{ CO }_{ 3 }^{ -2 }<CO$$

C
$$CO<{ CO }_{ 3 }^{ -2 }<{ CO }_{ 2 }$$

D
$${ CO }_{ 3 }^{ -2 }<{ CO }_{ 2 }<CO$$

Solution
Question 6
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Consider the following three halides:
(i) $${CH}_{3}-{CH}_{2}Cl$$
(ii) $${CH}_{2}=CH-Cl$$
(iii) $${C}_{6}{H}_{5}-Cl$$
Arrange $$C-Cl$$ bond lenght of these compounds in decreasing order:

A
$$i> ii> iii$$

B
$$i> iii> ii$$

C
$$iii> ii> i$$

D
$$ii> iii> i$$

Solution
Question 7
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A reagent which lowers the oxidation number of an element in a given substance is known as

A
oxidation agent

B
reduction

C
reducing agent

D
oxidation

Solution
Question 8
1 / -0

The $$X-X$$ bond length is $$1.00\mathring{A}$$ and $$C-C$$ bond length is $$1.54\mathring{A}$$. The $$C-X$$ bond length is likely to be

A
$$0.80\mathring {A}$$

B
$$1.18\mathring {A}$$

C
$$1.57\mathring {A}$$

D
$$1.68\mathring {A}$$

Solution
Question 9
1 / -0

Which molecule has zero dipole moment?

A
$$Xe{F}_{2}$$

B
$${SO}_{2}$$

C
$${CH}_{4}$$

D
p-dimethoxy benzene

Solution
Question 10
1 / -0

During change of $$NO^{+}\rightarrow NO$$, the electron is added to

A
$$\sigma$$-orbital

B
$$\pi $$-orbital

C
$$\sigma \quad ^{ \ast }$$-orbital

D
$$\pi \quad ^{ \ast }$$-orbital