States of Matte...

Rain drops are spherical in shape because of

The vapour pressure of pure benzene at $$88^oC$$ is 957 mm and that of toluene at the same temperature is 379.5 mm. Calculate the composition of benzene-toluene mixture boiling at $$88^oC$$.

The specific heat of a bivalent metal is 0.16. The approximate equivalent mass of the metal will be:

Four flasks of 1 litre capacity each arc separately filled with gases $$H_2, He, O_2$$ and $$O_3$$. At the same temperature and pressure the ratio of the number of atoms of these gases present in different flasks would be: 

In the reaction, $$N_2 + 3H_2 \rightarrow 2NH_3$$, the ratio of volumes of nitrogen, hydrogen and ammonia is 1 : 3: 2. These figures illustrate the law of: 

At $$25^oC$$, the total pressure of an ideal solution obtained by mixing 3 mole of A and 2 mole of B, is 184 torr. What is the vapour pressure (in torr) of pure B at the same temperature (Vapour pressure of pure A at $$25^oC$$ is 200 torr.)?

Vapour pressure of pure $$A(p^0_A)=100$$ mm Hg
Vapour pressure of pure $$B(p^0_B)=150$$ mm Hg

Equal volumes of different gases at any definite temperature and pressure have:

Mole fraction of the component A in vapour phase is $$x_1$$ and mole fraction of component A in liquid mixture is $$x_2$$, then ($$p^0_A =$$ vapour pressure of pure A; $$p^0_B =$$ vapour pressure of pure B), the total vapour pressure of liquid mixture is :

The following graphs illustrate: