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States of Matter Test - 49

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States of Matter Test - 49
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  • Question 1
    1 / -0
    The vapour pressure of pure $$CHCl_{3}$$ and $$CH_{2}Cl_{2}$$ are $$200$$ and $$41.5\ atm$$ respectively. The weight of $$CHCl_{3}$$ and $$CH_{2}Cl_{2}$$ are respectively $$11.9\ g$$ and $$17\ gm$$. The vapour pressure of solution will be
    Solution
    $$P_{CHCl_{3}}{0} = 200\ atm\ P_{CH_{3}Cl_{2}}{0} = 41.5\ atm$$
    $$n = \dfrac {11.9}{119}\ n = \dfrac {17}{85}$$
    $$= .1\ = .2$$
    $$P_{T} = P_{A}^{0} X_{A} + P_{B}^{0} X_{B}$$
    $$= 200x \dfrac {0.1}{.3}\ + \dfrac {41.5\times 0.2}{.3}$$
    $$= 94.33$$.
  • Question 2
    1 / -0
    On increasing the altitude at constant temperature, vapour pressure of liquid 
    Solution
    Vapour pressure is a temperature dependent phenomena and it does not change unless temperature is changed. On increasing altitude, the outside pressure decreases and to maintain that the rate of evaporation and condensation also changes which keeps vapour pressure constant. So answer is option C.
  • Question 3
    1 / -0
    The vapour pressure of pure $$M$$ and $$N$$ are $$700$$mm of $$Hg$$ and $$450 mm$$ of $$Hg$$ respectively.which of the following option is correct?
    Given :$$X_N,X_M$$- mole fraction of $$N$$ and $$M$$ in liquid phase
    $$Y_N,Y_M$$= mole fraction of $$N$$ and $$M$$ in vapour phase.
    Solution
    Solution:- (C) $$\dfrac{X_M}{X_N}<\dfrac{Y_M}{Y_N}$$
    Mole fraction of more voltatile component increase in vapour phase, i.e.,
    $$P_N^o<P_M^o$$
  • Question 4
    1 / -0
    In the ideal gas equation, the gas constant $$R$$ has the dimensions of:
    Solution
    $$PV = nRT \ R = \dfrac {PV} {nT} = litre . atm. K- mole$$
  • Question 5
    1 / -0
    A closed vessel contains equal number of nitrogen and oxygen molecules at a pressure of $$p\ mm$$. If nitrogen is removed from the system then the pressure will be:
    Solution
    At constant $$V, P\propto n$$

    $$\therefore$$ if no. of moles is halved then pressure will also reduce to $$p/2$$.

    Option C is correct.
  • Question 6
    1 / -0
    $$\Delta_f G^{\circ}$$ at 500 K for substance 'S' in liquid state and gaseous state are +100.7 kcal $$mol^{-1}$$ respectively. Vapour pressure of liquid 'S'' at 500 K is approximately equal to: 

    $$R = 2 cal K^{-1} mol^{-1}$$
    Solution

  • Question 7
    1 / -0
    Equal weights of methane and hydrogen are mixed in an empty container at $$25^oC$$. The fraction of the total pressure exerted by hydrogen is
    Solution
    $$\dfrac{n_{CH_2}}{n_{H_2}}=\dfrac{M_{H_2}}{M_{CH_2}}$$ ( for equal not ) $$=\dfrac{2}{16}=\dfrac{1}{8}$$

    $$\dfrac{n_{H_2}}{n_{CH_4}}=\dfrac{8}{1}\Rightarrow \dfrac{n_{H_2}}{n_{total}}=\dfrac{8}{9}=X_{H_2}$$

    $$\therefore P_{H_2}=X_{H_2}P_{total}\Rightarrow X_2 =\dfrac{P_{H_2}}{P_{total}}=\dfrac{8}{9}$$

    Option B
  • Question 8
    1 / -0
    The translational kinetic energy of an ideal gas depends only on its:
    Solution
    $$K.E. = \dfrac {3RT}{2}$$ it means that the Translational Kinetic energy of Ideal gas depends upon temperature only. 
  • Question 9
    1 / -0
    Kinetic energy of a gas depends upon its:
    Solution
    Kinetic energy $$ =\dfrac {3}{2} RT$$

    Hence, option D is correct.
  • Question 10
    1 / -0
    Which of the following gas mixture is not applicable to Dalton's law of partial pressure?
    Solution
    Mixture of $$SO_{2}$$ and $$Cl_{2}$$ are reacted chemically and forms $$SO_{2}Cl_{2}$$. 

    That is why mixture of these gases is not applicable for Dalton's law. 
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