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Thermodynamics Test - 40

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Thermodynamics Test - 40
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  • Question 1
    1 / -0
    $$C(s) + O_2(g) \to CO_2(g); \quad \Delta H = -94kcal$$

    $$2CO(g) + O_2(g) \to 2CO_2(g); \quad \Delta H = -135.2 kcal$$

    The heat of formation of $$CO(g)$$ is :
    Solution
    Given,
    $$C(s) + O_2(g) \to CO_2; \Delta H_1 = -94Kcal.$$       ....(1)

    $$2CO(g) + O_2(g) \to 2CO_2(g); \Delta H_2= - 135.2 K \ cal.$$          ....(2)

    $$\Delta H_f(CO)=?$$

    Now the formation of $$CO$$ is

    $$CO_2(g) + O_2(g) \to CO + \dfrac{1}{2}O_2(g)$$ ....(3)

    Then, $$\Delta H_3 = \dfrac{135.2}{2} = 67.6K\ cal$$

    $$\therefore $$ The required equation,

    $$C(s) + \dfrac{1}{2} O_2= CO(g); \Delta H_4 = ?$$ 

    Adding equation (1) and (3) we get

    $$C(s) + \dfrac{1}{2} O_2 \to CO(g)$$;

    $$\Rightarrow \Delta H = -94+67.6 = -26.4K cal$$.

    $$\therefore$$ The heat of formation of $$CO(g)$$ is $$-26.4\ K\ cal$$.

    Hence, te correct option is $$\text{A}$$
  • Question 2
    1 / -0
    Suppose that a reaction has $$\Delta H=-40kJ$$ and $$\Delta S=-50J/K$$. At what temperature range will it change from spontaneous to non-spontaneous ?
  • Question 3
    1 / -0
    Consider the reaction, $$2A_{(g)} + B_(g) rightleftarrow 2C_{(g)}$$ for which $$K_c = 350$$. If $$0.01$$ mole of each of the reactants and product are mixed in a $$2.0$$L flask, then the reaction quotient and the spontaneous direction of the system will be?
    Solution

  • Question 4
    1 / -0
    $$\Delta H$$ and $$\Delta S$$ are $$-283\ kJ$$ and $$-87\ J\ K^{-1}$$, respectively. It was intended to carry out this reaction at $$1000, 1500, 3000$$ and $$3500\ K$$. At which of these temperatures would this reaction be thermodynamically spontaneous?
    Solution

  • Question 5
    1 / -0
    Which of the following statements is wrong?
    Solution

  • Question 6
    1 / -0
    Which of the following is not true about a reversible reaction?
  • Question 7
    1 / -0
    $$2{H}_{2(g)}+{O}_{2(g)}\rightarrow 2{H}_{2}{O}_{(l)};\Delta H=-ve$$ and $$\Delta G=-ve$$. Then the reaction is
    Solution

  • Question 8
    1 / -0
    Which of the following expression for an irreversible process:
  • Question 9
    1 / -0
    In standard state the non spontaneous reaction among the following is:
    Solution
    Ans$$C$$-  freeging of water
    water exists in liquid state naturally at standard state $${ 25 }^{ \circ  }c=298k$$. Hence freezing of $${ H }_{ 2 }O$$ at 298k is non-spontaneous as ice will absorb heat from surroundings thereby gets converted to the liquid state as it is a natural process of is irreversible. 
  • Question 10
    1 / -0
    Answer the question based on the diagram involving $$1$$ mole of ideal gas.
    Process $$A\rightarrow B$$ represents:

    Solution
    Solution:- (B) isochoric process
    In process $$A \rightarrow B$$, as the volume is constant, thus the process represents isochoric process.
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