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Equilibrium Test - 55

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Equilibrium Test - 55
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  • Question 1
    1 / -0
    (A) If water is heated to 350 K, then pOH will increase to 8.
    (R) $$K_w$$ increases with increase in temperature.
    Solution
    If water is heated to 350 K, then pOH will increase to 8.
    $$K_w$$ increases with increase in temperature. As $$K_w$$ increases pOH increases, pH  decreases.

    So both (R) and (A) are true and reason is the. correct explanation of assertion.

    Hence option A is correct.

  • Question 2
    1 / -0
    Which of the following is not true for the equilibrium reaction? $$N_2(h)+O_2(g)\rightleftharpoons 2NO(g); \Delta H=180$$kJ $$mol^{-1}$$.
    Solution
    solution:
     option a:
    It's an endothermic reaction as $$\Delta H $$ is positive as temperature increases equilibrium will try to balnce it out by moving right side  so its true
    option b :
    on increasing pressure there is no change in equilibrium  as $$\Delta n =0$$
    option C :
    on increasing volume  there is no change in equilibrium  as $$\Delta n =0$$
    option d:
     It's an endothermic reaction as $$\Delta H $$ is positive as temperature increases equilibrium will try to balnce it out by moving right side  so it is not true 
    hence the correct opt: D
  • Question 3
    1 / -0
    Consider the following equilibrium system; $$SO_2(g)+\displaystyle\frac{1}{2}O_2(g)\rightleftharpoons SO_3(g)$$; set up in a cylinder fitted with a piston. Some inert gas is added and the piston is moved outwards to keep the total gaseous pressure constant. Predict which of the following is true?
  • Question 4
    1 / -0
    Which of the following would dissolve $$Pb(OH)_{2}$$ more than pure water?
    Solution

  • Question 5
    1 / -0
    The exothermic formation of $$ClF_{3}$$ is represented by the equation:
    $$Cl_{2}(g) + 3F_{2}(g) \rightleftharpoons 2ClF_{3}(g); \triangle H_{r} = -329\ kJ$$
    which of the following will increase the quantity of $$ClF_{3}$$ in an equilibrium mixture of $$Cl_{2}, F_{2}$$ and $$ClF_{3}$$?
  • Question 6
    1 / -0
    Which of the following does not contribute towards the formation of photochemical smog ?
    Solution
    Photochemical smog is formed by the combination of smoke/dust/fog articles with the oxides of Nitrogen (Like $$NO$$) and Hydrocarbons in the presence of sunlight. It is brown in colour ad hazy.
    Ozone ($$O_{3}$$) contributes towards photochemical smog as it acts as an initiator of various reactions that lead to the formation of photochemical smog.
    On the other hand, $$SO_{2}$$ does not contribute in any way towards photochemical smog.
    Hence, correct answer is (B) $$SO_{2}$$
  • Question 7
    1 / -0
    Solid ammonium carbonate dissociates as:$${ NH }_{ 2 }COO{ NH }_{ 4 }(s)\rightleftharpoons 2{ NH }_{ 3 }(g)+{ CO }_{ 2 }(g)$$. In a closed vessel solid ammonium carbonate is in equilibrium with its dissociation products. At equilibrium, ammonia is added such that the partial pressure of $${NH}_{3}$$ at new equilibrium now equals the original total pressure. Calculate the ratio of total pressure at new equilibrium to that of original total pressure.
  • Question 8
    1 / -0
    The exothermic formation of $$Cl{F}_{3}$$ is represented by the equation:

    $${ Cl }_{ 2(g) }+2{ F }_{ 2(g) }\rightleftharpoons 2Cl{ F }_{ 3(g) };\Delta { H }_{ r }=-329kJ\quad $$

    Which of the following will increase the quantity of $$Cl{F}_{3}$$ in an equilibrium mixture of $${Cl}_{2},{F}_{2}$$ and $$Cl{F}_{3}$$?
    Solution

    For the given reaction $$C{l_2}(g) + 2{F_2}(g) \rightleftharpoons 2Cl{F_3}(g)$$, the enthalpy change of the reaction is given as$$\vartriangle {H_r} =  - 329kJ$$ . We know that if the enthalpy change is negative then the reaction is an exothermic reaction. Therefore, according to Le Chatlier’s principle increasing the temperature will shift the equilibrium towards the side of the reactants and hinder the formation of the product.

    Removing $$C{l_2}$$ will result in the decrease in the quantity of the product, since the equilibrium of the reaction will move backward.

    By increasing the volume of the container the value of $${Q_c}$$ will become greater than the value of $${K_c}$$ hence favoring the backward reaction and resulting in the decrease of the quantity of the product.

    So, for the given reaction if we want to increase the quantity of the product $$Cl{F_3}$$ then the correct option will be to add $${F_2}$$ so that the to decrease the concentration of $${F_2}$$ and to bring the system into equilibrium the reaction will move forward and hence the quantity of the product $$Cl{F_3}$$ will increase.

     Hence, the correct option is C.) Adding $${F_2}$$

  • Question 9
    1 / -0
    The reaction, $$ZnO(s)+CO(g)\rightleftharpoons Zn(g)+{ CO }_{ 2 }(g)$$ has an equilibrium constant of $$1$$ atm at $$1500K$$. The equilibrium partial pressure of zinc vapour in a reaction vessel if an equimolar mixture of $$CO$$ and $${CO}_{2}$$ is brought into contact with solid $$ZnO$$ at $$1500K$$ and the equilibrium is achieved at $$1$$ atm is?
  • Question 10
    1 / -0
    In which one of the following equilibria, the increase of pressure over the equilibrium will favour the backward reaction?
    Solution
    In the decomposition reaction of $$NH_{3}$$ the number of moles of products formed is greater than that of reactant involved.
    $$2NH_{3}\rightleftharpoons N_{2} + 3H_{2}$$
    According to Le-Chatelier's principle, the increase of pressure on a chemical equilibrium shift in that direction in which the number of gaseous molecules decreases and vice-versa thus in this reaction, increase in pressure favours the backward reaction.
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