Equilibrium Test

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Equilibrium Test - 58

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Weekly Quiz Competition

Question 1
1 / -0

For the following equilibrium
$${\text{N}}{{\text{H}}_{\text{4}}}{\text{HS}}\left( {\text{s}} \right) \rightleftharpoons {\text{N}}{{\text{H}}_{\text{3}}}\left( {\text{g}} \right){\text{ + }}{{\text{H}}_{\text{2}}}{\text{S}}\left( {\text{g}} \right)$$; partial pressure of $${\text{N}}{{\text{H}}_{\text{3}}}$$ will increase

A
If $${\text{N}}{{\text{H}}_{\text{3}}}$$ is added after equilibrium is established

B
If $${{\text{H}}_{\text{2}}}{\text{S}}$$ is added after equilibrium is established

C
$${\text{N}}{{\text{H}}_{\text{4}}}{\text{HS}}$$ is added into the container

D
Volume of the flask is decreased

Solution

The partial pressure of $${\text{N}}{{\text{H}}_3}$$ will increase if $${\text{N}}{{\text{H}}_3}$$ is added in accorandce with le chaterlier principle..because according to that on increasing the pressure the rxn shift to that side which have fewer no. of moles of gases.
Hence option (A) is correct.
Question 2
1 / -0

For $$N{H_4}H{S_{\left( s \right)}} \to N{H_{3\left( g \right)}} + {H_2}{S_{9\left( g \right)}},{K_p} = 100\,at{m^2}$$, equilibrium pressure equals to:

A
$$40$$ atm

B
$$400$$ atm

C
$$20$$ atm

D
$$100$$ atm

Solution
Question 3
1 / -0

The correct order of equilibrium constant for the reactions is:
$$H_2CO+H_2O\quad \begin{matrix} { K }_{ 1 } \\ { \rightleftharpoons } \end{matrix}\quad H_2C(OH)_2$$

$$CH_3CH_2CHO+H_2O\quad \begin{matrix} { K }_{ 2 } \\ { \rightleftharpoons } \end{matrix}\quad CH_3CH_2CH(OH)_2$$

$$CH_3COCH_3+H_2O\quad \begin{matrix} { K }_{ 3 } \\ { \rightleftharpoons } \end{matrix}\quad CH_3C(OH)_2CH_3$$

A
$$K_1>K_2>K_3$$

B
$${ K }_{ 1 }<{ K }_{ 2 }<{ K }_{ 3 }$$

C
$$K_1>K_3>K_2$$

D
$${ K }_{ 1 }<{ K }_{ 2 }>{ K }_{ 2 }$$
Question 4
1 / -0

Which buffer solution has maximum $$pH?$$

A
mixture which is $$0.1$$ M in $$ \mathrm { CH } _ { 3 } \mathrm { COOH } $$ and $$0.1$$ M in $$ \mathrm { CH } _ { 3 } \mathrm { COONa } \left[ \mathrm { pK } _ { \mathrm { a } } \left( \mathrm { CH } _ { 3 } \mathrm { COOH } \right) = 4.74 \right] $$

B
mixture which is $$0.2$$ M $$ \mathrm { CH } _ { 3 } \mathrm { COOH } $$ and $$0.2$$ M in $$ \mathrm { CH } _ { 3 } \mathrm { COONa } $$

C
mixture which is $$0.1$$ M in $$ \mathrm { NH } _ { 4 } \mathrm { Cl } $$ and $$0.1$$ M in $$ \mathrm { NH } _ { 4 } \mathrm { OH } \left[ \mathrm { pK } _ { \mathrm { a } } \left( \mathrm { NH } _ { 4 } ^ { + } \right) = 9.26 \right] $$

D
all the solution have equal $$pH$$ which is $$4.74$$
Question 5
1 / -0

At 298 K $$0.01 M\ { NH }_{ 4 }OH$$ solution is $$4.3\%$$ ionised.The ionization constant of $${ NH }_{ 4 }OH $$ is :

A
$$1.84\times10^{-5}$$

B
$$2.05\times 10^{-5}$$

C
$$1.62\times 10^{-4}$$

D
$$1.84\times 10^{-4}$$
Question 6
1 / -0

Solubility of silver cyanide is maximum in

A
Acidic buffer solution

B
Basic buffer solution

C
In pure water

D
Equal in all
Question 7
1 / -0

At $$100^\circ C$$, value of $$K_{w}$$ is

A
$$1.0\times 10^{-14}\quad m^{2}$$

B
less than $$1.0\times 10^{-14}\quad m^{2}$$

C
greater than $$1.0\times 10^{-14}\quad m^{2}$$

D
Zero

Solution

At higher temperature the value of $$kw$$ increases.This is in according with le-chatelier principle.
At $$100^o kw=51.3\times 106{-14}$$
C is the correct answer.
Question 8
1 / -0

$$As_2S_3$$ solution has negative charge, capacity to precipitate is highest in:

A
$$AlCl_3$$

B
$$Na_3PO_4$$

C
$$CaCl_2$$

D
$$K_2SO_4$$

Solution

Solution:- (A) $$Al{Cl}_{3}$$
According to Hardy-Schulze rule, more is the valence of effective ion, greater is its coagulating power.
Hence $${As}_{2}{S}_{3}$$ precipitate the most in $$Al{Cl}_{3}$$.
Question 9
1 / -0

If the pressure of $$N_2/H_2$$ mixture in a closed apparatus is 100 atm and 20% of the mixture reacts,then the pressure at same temperature would be:

A
100

B
90

C
85

D
80

Solution

Solution:- (B) $$90$$

$${N}_{2} + 3 {H}_{2} \longrightarrow 2 N{H}_{3}$$

From the above reaction,

$$4$$ mole of reactant produces $$2$$ mole of $$N{H}_{3}$$

Therefore,

$$20 \%$$ mixture reacts to form $$10 \% \; N{H}_{3}$$.

Thus, $$80 \%$$ mixture and $$10 \% \; N{H}_{3}$$, i.e., $$90 \%$$ of mixture is left.

$$\because \; 100 \%$$ mixture has $$100 \; atm$$ pressure.

$$\therefore$$ Total pressure left $$= 90 \; atm$$
Question 10
1 / -0

Calculate the degree of ionization of 0.04M HOCl solution having ionization constant $$1.25\times { 10 }^{ -4 }$$?

A
0.025

B
0.25

C
0.5

D
0.055

Solution

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Re-Attempt Weekly Quiz Competition

Equilibrium Test - 58

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Equilibrium Test - 58

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Question 1

If $${\text{N}}{{\text{H}}_{\text{3}}}$$ is added after equilibrium is established

If $${{\text{H}}_{\text{2}}}{\text{S}}$$ is added after equilibrium is established

$${\text{N}}{{\text{H}}_{\text{4}}}{\text{HS}}$$ is added into the container

Volume of the flask is decreased

Solution

Question 2

$$40$$ atm

$$400$$ atm

$$20$$ atm

$$100$$ atm

Solution

Question 3

$$K_1>K_2>K_3$$

$${ K }_{ 1 }<{ K }_{ 2 }<{ K }_{ 3 }$$

$$K_1>K_3>K_2$$

$${ K }_{ 1 }<{ K }_{ 2 }>{ K }_{ 2 }$$

Question 4

mixture which is $$0.1$$ M in $$ \mathrm { CH } _ { 3 } \mathrm { COOH } $$ and $$0.1$$ M in $$ \mathrm { CH } _ { 3 } \mathrm { COONa } \left[ \mathrm { pK } _ { \mathrm { a } } \left( \mathrm { CH } _ { 3 } \mathrm { COOH } \right) = 4.74 \right] $$

mixture which is $$0.2$$ M $$ \mathrm { CH } _ { 3 } \mathrm { COOH } $$ and $$0.2$$ M in $$ \mathrm { CH } _ { 3 } \mathrm { COONa } $$

mixture which is $$0.1$$ M in $$ \mathrm { NH } _ { 4 } \mathrm { Cl } $$ and $$0.1$$ M in $$ \mathrm { NH } _ { 4 } \mathrm { OH } \left[ \mathrm { pK } _ { \mathrm { a } } \left( \mathrm { NH } _ { 4 } ^ { + } \right) = 9.26 \right] $$

all the solution have equal $$pH$$ which is $$4.74$$

Question 5

$$1.84\times10^{-5}$$

$$2.05\times 10^{-5}$$

$$1.62\times 10^{-4}$$

$$1.84\times 10^{-4}$$

Question 6

Acidic buffer solution

Basic buffer solution

In pure water

Equal in all

Question 7

$$1.0\times 10^{-14}\quad m^{2}$$

less than $$1.0\times 10^{-14}\quad m^{2}$$

greater than $$1.0\times 10^{-14}\quad m^{2}$$

Zero

Solution

Question 8

$$AlCl_3$$

$$Na_3PO_4$$

$$CaCl_2$$

$$K_2SO_4$$

Solution

Question 9

100

90

85

80

Solution

Question 10

0.025

0.25

0.5

0.055

Solution

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