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Redox Reactions Test - 49

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Redox Reactions Test - 49
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  • Question 1
    1 / -0
    In which of the following compounds iron has lowest oxidation state :-
    Solution

  • Question 2
    1 / -0
    Which of the following, oxidation number of carbon is -1?
    Solution
    For benzene let oxidation number of C be x,
    $$6x+6\times(+1) \implies x=-1$$

    The oxidation state of carbon in benzene is -1 and the oxidation state of hydrogen in benzene is +1. In a C-H bond(this bond is non-polar covalent), the H is treated as if it has an oxidation state of +1. This means that every C-H bond will decrease the oxidation state of carbon by 1.
  • Question 3
    1 / -0
    In which reaction, there is change in oxidation number of N atom ?
  • Question 4
    1 / -0
    Reaction $$(A) S^{-2} + 4 H_2O_2 \rightarrow  SO^{2-}_4 + 4H_2O$$
    $$(B)Cl_2 + H_2O_2 \rightarrow 2HCl + O_2$$
    The true statement regarding the above reactions is :
    Solution

  • Question 5
    1 / -0
    The brown ring complex compound is formulated as $$[Fe(H_2O)_5NO]SO_4$$. The oxidation state of iron is:
    Solution
    Brown ring complex is an iron complex of great significance in inorganic chemistry and salt analysis. 
    Its formula: $$[Fe(H_2O)_5NO]SO_4$$ (coordination compound)
    In this complex, $$NO$$ is in oxidation state of $$+1.$$
    So,$$ [Fe(H_2O)_5NO]^{+2}$$       $$SO_4^{-2}$$
            $$\overline {x}$$      $$\overline {0}$$          $$\overline {+1}$$
    $$x+1=+2$$
    $$x=+1$$
  • Question 6
    1 / -0
    Oxidation number of oxygen atom in  $$O_3$$ molecules is:
    Solution
    Its common name is ozone and plays a very important role of protecting earth from harmful UV rays by forming its blanket around earth.
    average oxidation state$$=\cfrac {-1+1+0} {3}= 0$$

  • Question 7
    1 / -0
    Which of the following is not a redox change ?
    Solution
     $$Ba{O}_{2} + {H}_{2}S{O}_{4} \longrightarrow BaS{O}_{4} + {H}_{2}{O}_{2}$$
    A redox reaction is any chemical reaction in which the oxidation number of a molecule, atom, or ion changes by gaining or losing an electron.
    $$Ba{O}_{2} + {H}_{2}S{O}_{4} \longrightarrow BaS{O}_{4} + {H}_{2}{O}_{2}$$
    As we know that the oxidation no. of oxygen in peroxide is -1.
    Since $$Ba{O}_{2}$$ and $${H}_{2}{O}_{2}$$ are peroxides, hence the oxidation number of oxygen in $$Ba{O}_{2}$$ and $${H}_{2}{O}_{2}$$ is -1 as the oxidation no. of oxygen in peroxide is -1.
    $$\therefore$$ Oxidation number of barium and hydrogen in $$Ba{O}_{2}$$ and $${H}_{2}{O}_{2}$$ are +2 and +1 respectively.
    The oxidation number of barium and hydrogen in $$BaS{O}_{4}$$ and $${H}_{2}S{O}_{4}$$ are +2 and +1 respectively.
    The oxidation number of sulphur in $${H}_{2}S{O}_{4}$$ and $$BaS{O}_{4}$$ in same, i.e., +2.
    The oxidation number of oxygen in $${H}_{2}S{O}_{4}$$ and $$BaS{O}_{4}$$ in same, i.e., -2.
    Since the oxidation state of any atom in the above reaction is not changing, hence the above reaction is not a redox reaction.
  • Question 8
    1 / -0
    Which of the following is not a redox reaction ?
    Solution

  • Question 9
    1 / -0
    Sulphur has highest oxidation state in:
  • Question 10
    1 / -0
    Heated saw dust catches fire when a drop of concentrated nitric acid is added to it. This is due to
    Solution

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