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Hydrogen Test - 19

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Hydrogen Test - 19
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  • Question 1
    1 / -0
    In the hydrogen peroxide molecule :
    Solution
    Hydrogen peroxide $$(H_2O_2)$$ is a nonplanar molecule with (twisted) symmetry. It is non–linear, non–planar molecule with a open book structure. The $$–O–O–$$ linkage is called peroxy linkage. The structure is given in the figure above. 

  • Question 2
    1 / -0
    In case of $$H_{2}O_{2}$$ in solid state, the angle between the planes containing $$H-$$atoms is:
    Solution

    There are two planes in this structure and each plane has one O-H pair, the angle between both the planes is 90.2°, The O-O bond length is 145.8 pm and the O-H bond length is 98.8 pm.

    Hence option B is correct.

  • Question 3
    1 / -0
    In $$H_{2}O_{2}$$ molecule the O-O bond length is:
    Solution
    The bond length is slightly greater than length of a single bond, due to repulsion between the lone pairs of oxygen atoms.
  • Question 4
    1 / -0
    The angle between the planes of $$H_{2}O_{2}$$ molecule in gaseous phase is:
    Solution
    $$C$$ is the correct option which can be seen from the diagram.

  • Question 5
    1 / -0
    What is the solution used for the preparation of hydrogen peroxide by electrolytic procedure?
    Solution
    Hydrogen peroxide is manufactured by the electrolysis of 50% sulphuric acid followed by vacuum distillation. Here, 30% of pure hydrogen peroxide is obtained.
    Option B is correct.
  • Question 6
    1 / -0
    In $$H_{2}O_{2}$$, the degree of hydrogen bonding is:
    Solution
    Due to the presence of two oxygen atoms in $$H_2O_2$$, there would be four hydrogen bonds corresponding to each molecule. Whereas, in water there would be only three hydrogen bonds per molecule.
  • Question 7
    1 / -0
    Hydrogen peroxide has a:
    Solution

    The structure of $$H_2O _2$$ is not planar but open book structure. The O-O-H bond angle is 101.5$$^o$$ and the O-O single bond distance is 1.48 A$$^o$$.

    Hence, option D is correct.

  • Question 8
    1 / -0

    Statement-1: Both sodium and hydrogen have outer electronic configuration $$ns^{1}$$ but hydrogen is less reactive than sodium.
    Statement-2: Hydrogen has greater ionisation energy.
    Solution
    Both sodium and hydrogen is having same outer electronic configuration $$ns^1$$ but hydrogen have less reactivity because the ionization potential of $$Na$$ is less. Hence, it can loose its electron easily and participates in chemical reaction easily, so reason is the correct explanation for assertion so option A would be correct.
  • Question 9
    1 / -0
    $$30$$ volume hydrogen peroxide means:
    Solution
    $$30$$ volume hydrogen peroxide means, $$1$$ ml of hydrogen peroxide solution liberates $$30$$ ml of oxygen gas at STP

    $$1$$ ml $$= 1\:\text{cm}^3$$

    Option C is correct.
  • Question 10
    1 / -0
    One ml of $$H_{2}O_{2}$$ solution gives $$50$$ ml of $$O_{2}$$ at NTP, so it is:
    Solution
    $$1$$ ml of hydrogen peroxide gives $$50$$ ml of oxygen at NTP means, $$50$$ volume hydrogen peroxide.
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