Hydrogen Test

Result

Hydrogen Test - 49

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Weekly Quiz Competition

Question 1
1 / -0

Which of the following reaction cannot give hydrogen gas?

A
$$Zn+con.H_{2}SO_{4}$$

B
$$C$$ + very dil $$H_{2}SO_{4}$$

C
$$Mn$$ + extremely dil $$HNO_{3}$$ ( 2 % )

D
$$Pb$$+dil $$HNO_{3}$$

Solution
Question 2
1 / -0

The compound that gives $$H_2O_2$$ on treatment with dilute $$H_2SO_4$$ is:

A
$$PbO_2$$

B
$$BaO_2.8H_2O+O_2$$

C
$$MnO_2$$

D
$$TiO_2$$

Solution
Question 3
1 / -0

The structure of $$H_2O_2$$ is :

A
Half open book like

B
Linear

C
Closed book

D
Pyramidal

Solution

Option-A
The structure of hydrogen peroxide is non-planar. H₂O₂ has an open book structure with O – O spins as shown in the figure.
Question 4
1 / -0

The boiling point of water is exceptionally high because:

A
There is covalent bond between H and O

B
Water molecules are linear

C
Water molecules associate due to hydrogen bonding

D
Water molecules are not linear.

Solution

It is due to hydrogen bonding.
In H₂O oxygen is highly electronegative and due to this the electron of hydrogen deviates towards oxygen making it a polar molecule that is creating delta positive charge on hydrogen and delta negative charge on oxygen.
Because of this the hydrogen atom forms hydrogen bonding with oxygen of other water molecules having delta negative charge.
The hydrogen bonding makes the overall bond of the molecule strong. So while boiling water first the hydrogen bond has to be broken and then the hydrogen and oxygen bond will be broken. And hence the boiling point is exceptionally high.
Question 5
1 / -0

The reaction of water with ammonia is given the following equation, $$H_2O+NH_3\rightleftharpoons NH^+_4+OH^-$$. In this reaction water behaves as :

A
neutral

B
base

C
acid

D
both acid and base

Solution
Question 6
1 / -0

An element reacts with hydrogen to form a compound 'A' which on treatment with water liberates hydrogen gas. The element can be:

A
Nitrogen

B
Chlorine

C
Selenium

D
Calcium

Solution

Among all the elements, group II Calcium reacts rapidly with cold water to give hydrogen and a white precipitate of calcium hydroxide
$$Ca+2H_ 2O\rightarrow Ca(OH)_ 2+H_ 2\uparrow $$
Hence the correct answer is [D}
Question 7
1 / -0

In which of the following hydrides, the law of constant composition does not hold good:

A
Saline hydride

B
Metallic hydride

C
Molecular hydride

D
All of these

Solution
Question 8
1 / -0

Hydrogen can be placed in VIIA ( 17th group) of periodic table because:

A
hydrogen forms hydrides like $$NaH$$

B
hydrogen has isotopes $$D$$ and $$T$$

C
it is light

D
hydrogen combines with halogens

Solution

(a) Hydrogen forms hydrides like NaH similar to Group 17 halogens (NaF, Nacl, NaBr, NaI).
(b) Hydrogen, as well as halogen, are non-metals
(c) Hydrogen and halogens both can form an ionic and covalent bond.
(d) With respect to electronic configuration, similar to halogens, hydrogen requires only one electron to complete its valence shell and for achieving noble gas electronic configuration.
Hence Correct answer is [A].
Question 9
1 / -0

In the laboratory $$H_2O_2$$ is prepared by the action of :

A
cold dilute $$H_2SO_4$$ on hydrated $$BaO_2$$

B
dil. $$HCl$$ on $$MnO_2$$

C
cold $$H_2SO_4$$ on $$MnO_2$$

D
aqueous alkali on $$Na_2O_2$$

Solution
Question 10
1 / -0

The bond angle and dipole moment of water respectively are:

A
$$109.5^o, 1.84\ D$$

B
$$107.5^o, 1.56\ D$$

C
$$104.5^o, 1.84\ D$$

D
$$102.5^o, 1.56\ D$$

Solution

The bond angle of water is $$104.45$$ degrees due to the presence of two lone pairs of electrons.

The dipole moment arises because oxygen is more electronegative than hydrogen; the oxygen pulls in the shared electrons and increases the electron density around itself.

This creates an electric dipole moment vector, with the partial negative charge on the oxygen atom.

There are two $$O-H$$ bonds, so the dipole moment of the molecule is the resultant vertical vector projection of the individual diagonal dipole vectors.

The dipole moment of water is $$1.84\ D$$.

$$\mathbf{Hence\ the\ correct\ answer\ is\ option\ (C)}$$.