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Measures of Central Tendency Test - 6

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Measures of Central Tendency Test - 6
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  • Question 1
    1 / -0

    What is the median of the following set of scores? 19, 5, 12, 10, 14?

    Solution

    Arranging the data, in ascending order, Median = size of  (N+1)/2 item i.e. 12 .

  • Question 2
    1 / -0

     Approximately what percentage of scores falls within one standard deviation of the mean in a normal distribution?

    Solution

    As per empirical rule, about 68% score falls in one standard deviation of mean. 

  • Question 3
    1 / -0

    Suppose a researcher is concerned with a nominal scale that identifies users versus nonusers of bank credit cards. The measure of central tendency appropriate to this scale is the

    Solution

    Here, Mode is the most appropriate measure. Mode is the most frequently observed data value.

  • Question 4
    1 / -0

    What is the mean of this set of numbers: 4, 6, 7, 9, and 2000000?

    Solution

    Arithmetic mean by direct method isthe sum of all observations in a seriesdivided by the total number ofobservations. Mean = 4+6+7+9+2000000 = 2000026/5= 400005.2

  • Question 5
    1 / -0

    The mean of 11 numbers is 7. One of the numbers, 13, is deleted. What is the mean of the remaining 10 numbers?

    Solution

    Given Sum of all observations = 11x7=77

    Correct Sum of all observations = 77-13 = 64

    Correct total number of observations= 11-1= 10

    Correct Mean = Correct Sum of all observations/ Correct total number of observations= 64/10 = 6.4

  • Question 6
    1 / -0

    The mean of ten numbers is 58. If one of the numbers is 40, what is the mean of the other nine?

    Solution

    Mean  is calculated  as the sum of the values of all observations divided by the number of observations
    Mean = 58, N= 10 
    sum of the values of all observations = 58 x 10 = 580
    Corrected sum of the values of all observations = 580 - 40 = 540
    Corrected number of observations = 10 – 1 = 9
    Correct Mean = 540/9 = 60
     

  • Question 7
    1 / -0

    A batsman scores the following number of runs in 6 innings: 36, 35, 50, 46, 60, and 55. Calculate the mean runs scored in an inning.

    Solution

    Mean is calculated as the sum of the values of all observations divided by the number of observations
     N= 6
    Sum of the values of all observations = 36+35+50+46+60+55 = 282
    Mean = 282/6 = 47
     

  • Question 8
    1 / -0

    If the mean of five observations x, x + 2, x + 4, x + 6, x + 8 is 11. Find the mean of 1st three observations

    Solution

    Mean is calculated as the sum of the values of all observations divided by the number of observations
     N= 3
    Sum of the values of 1st. three observations = 11+9+7= 27
    Mean = 27/3 = 9

  • Question 9
    1 / -0

    The mean of 40 observations was 160. It was detected on re-checking that the value 165 was wrongly copied as 125 for computation of mean. Find the correct mean.

    Solution

    Mean is calculated as the sum of the values of all observations divided by the number of observations
     N= 40 , Mean = 160
    Sum of the values of all observations =  40 x 160 = 6400
    Sum of the values of all observations after correction= 6400 -125 = 6275+165 = 6440
    Correct Mean = 6440/40 = 161

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