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Correlation Test - 12

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Correlation Test - 12
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  • Question 1
    1 / -0
    If $$n=10, \sum x=4,\sum y=3, \sum x^2=8,\sum y^2=9$$ and $$\sum xy=3,$$ then the coefficient of $$r_{x,y}$$ is
    Solution
    Correlation coefficient 
    $${ r }_{ x,y }=\dfrac { n\sum { xy } -\sum { x } \sum { y }  }{ \sqrt { \left[ n\sum { { x }^{ 2 }-{ \left( \sum { x }  \right)  }^{ 2 } }  \right] \left[ n\sum { { y }^{ 2 }-{ \left( \sum { y }  \right)  }^{ 2 } }  \right]  }  } $$

    $$=\displaystyle\frac { 30-12 }{ \sqrt { 64\times 81 }  } $$
    $$\Rightarrow r_{x,y}=\dfrac{1}{4}$$
  • Question 2
    1 / -0
    Choose the statement which consists of two  positively correlated variables.
    Solution
    A positive correlation is a relationship between two variables where if one variable increases, the other one also increases. A positive correlation also exists in one decreases and the other also decreases.
    In the given options only option (A) has both positive variables.
  • Question 3
    1 / -0

    Directions For Questions

    Correlation is a statistical method or statistical technique that measures quantitative relationship between different variables like price & demand. Correlation between different variables may either be positive or negative. When two variable move in the same direction i.e. when one increases other also increases & vice versa & when two variable change in different directions are the cause of positive & negative correlation.
    In case of linear correlation, the two sets of data's show some fixed proportion to each other & therefore form a straight line on a graph paper. In case of non linear correlation, on the other hand the two sets of data's do not show any fixed proportion to each other, and therefore their graphs are different from the graphs of linear correlation. The degree of correlation refers to the coefficient of correlation. There are several degree of correlation like perfect positive, perfect negative high positive,high negative. Sometime variables are uncorrelated & degree of correlation in such cases is O.
    Consider the Scattered diagrams

    On the basis of above information answer the following questions

    ...view full instructions

    If the value of correlation $$ \displaystyle r=\frac{1}{2} $$ or $$ \displaystyle r= - \frac{1}{2} $$, then correlation is called
    Solution
    When correlation between two series or variables is neither large nor
    small, then it is called moderate degree correlation. It may be positive
    moderate or negative moderate. For positive moderate, correlation the
    value of $$\displaystyle r=\frac{1}{2}$$ & for negative moderate
    correlation the value of $$\displaystyle r=-\frac{1}{2}$$
    so choice (d) is correct 
  • Question 4
    1 / -0
    A strong positive association between x and y is depicted by which of the following graphs?
    Solution
    A strong association implies that there must be seen a concentrated set of points in the $$x-y$$ plane.
    Also, a positive association implies that the points must be going upwards, meaning that as $$x$$ increases, correspondingly $$y$$ increases too.
    This kind of set is visible in option D.
  • Question 5
    1 / -0
    The marks obtained by nine students in physics and Mathematics are given below:
    Physics486072625640395230
    Mathematics627865703854603231
    calculate spearman's coefficient.
    Solution
    Descending order arranged data will be as follows:
    Physics: $$72,62,60,56,52,48,40,39,30$$
    MAthematics: $$78,70,65,62,60,54,38,32,31$$
    Thus data will be

    Physics$$(P)$$

    Mathematics $$(M)$$

    Rank $$(P)$$

    Rank $$(P)$$

    $$|d|$$

    $$d^2$$

    48

    60

    72

    62

    56

    40

    39

    52

    30

    62

    78

    65

    70

    38

    54

    60

    32

    31

    6

    3

    1

    2

    4

    7

    8

    5

    9

    4

    1

    3

    2

    7

    6

    5

    8

    9

    2

    2

    2

    0

    3

    1

    3

    3

    0

    4

    4

    4

    0

    9

    1

    9

    9

    0

    $$n=9,\quad \sum d^2=40$$

    $$r=1-\cfrac{6\sum d^2}{n(n^2-1)}=1-\cfrac{40\times 6}{9(9^2-1)}=1-\cfrac{240}{720}=0.66$$

  • Question 6
    1 / -0
    The coefficient of correlation is always between
    Solution
    $$\Rightarrow$$  Correlation coefficients are expressed as values between $$-1$$ and $$+1$$. 
    $$\Rightarrow$$  A coefficient of $$+1$$ indicates a perfect positive correlation: A change in the value of one variable will predict a change in the same direction in the second variable. 
    $$\Rightarrow$$  A coefficient of $$-1$$ indicates a perfect negative correlation: A change in the value of one variable predicts a change in the opposite direction in the second variable. 
  • Question 7
    1 / -0
    FInd the rank correlation from the following data:
    S. No.12345678910
    Rank Differences-2-4-1320-233-2
    Solution

    Sl.No

    Rank Difference $$(d)$$

    $$d^2$$

    1.

    2.

    3.

    4.

    5.

    6.

    7.

    8.

    9.

    10.

    -2

    -4

    -1

    3

    2

    0

    -2

    3

    3

    -2

    4

    16

    1

    9

    4

    0

    4

    9

    9

    4

     $$\sum d^2=60,\quad n=10$$

    $$r=1-\cfrac{6\sum d^2}{n(n^2-1)}$$

    $$r=1-\cfrac{6(60)}{10(10^2-1)}$$

    $$r=1-\cfrac{360}{990}$$

    $$r=0.6363....\approx 0.64$$

  • Question 8
    1 / -0
    The marks in history and mathematics of twelve students in a public examination are given below. Calculate a coefficient of correlation by ranks.
    StudentABCDEFGHIJKL
    History693639716776402085655534
    Mathematics335271257922838124354664

    Solution

    Students

    History $$(H)$$

    Mathematics$$(M)$$

    Rank $$(H)$$

    Rank$$(M)$$

    $$|d|$$

    $$d^2$$

    A

    B

    C

    D

    E

    F

    G

    H

    I

    J

    K

    L


    69

    36

    39

    71

    67

    76

    40

    20

    85

    65

    55

    34

     

    33

    52

    71

    25

    79

    22

    83

    81

    24

    35

    46

    64

    4

    10

    9

    3

    5

    2

    8

    12

    1

    6

    7

    11

    9

    6

    4

    10

    3

    12

    1

    2

    11

    8

    7

    5


    5

    4

    5

    7

    2

    10

    7

    10

    10

    2

    0

    6

     


    25

    6

    25

    49

    4

    100

    49

    100

    100

    4

    0

    36

     

    $$n=12,\quad \sum d^2=508$$

    $$r=1-\cfrac{6\sum d^2}{n(n^2-1)}=1-\cfrac{6\times 508}{12(12^2-1)}=1-\cfrac{3048}{1716}=-0.77$$

  • Question 9
    1 / -0
    If increase in value of one variable is not accompnied by the proportional decrease in second variable, then corrrelation between two variables is
    Solution
    In general ,
    1) Increase in the value of one is followed by a decrease in the value of the other, and a decrease in the value of one is followed by a decrease in the value of the other, and a decrease in the value of one is followed by an increase in the value of the other is called as negative corrrelation 
    2) when the values of the variables under study change at different ratios, it is a case of imperfect correlation.

    hence in the given statement which satisfies these two statement and hence here the corrrelation is called as imperfect negative.

  • Question 10
    1 / -0
    The marks in History and Mathematics of twelve students in a public examination are given below. Calculate a coefficient of correlation by ranks.
    Student$$A$$$$B$$$$C$$$$D$$$$E$$$$F$$$$G$$$$H$$$$I$$$$J$$$$K$$$$L$$
    History$$69$$$$36$$$$39$$$$71$$$$67$$$$76$$$$40$$$$20$$$$85$$$$65$$$$55$$$$34$$
    Mathematics$$33$$$$52$$$$71$$$$25$$$$79$$$$22$$$$83$$$$81$$$$24$$$$35$$$$46$$
    $$64$$

    Interpret the result.
    Solution

    Students

    History $$(H)$$

    Mathematics$$(M)$$

    Rank $$(H)$$

    Rank$$(M)$$

    $$|d|$$

    $$d^2$$

    A

    B

    C

    D

    E

    F

    G

    H

    I

    J

    K

    L

    69

    36

    39

    71

    67

    76

    40

    20

    85

    65

    55

    34

    33

    52

    71

    25

    79

    22

    83

    81

    24

    35

    46

    64

    4

    10

    9

    3

    5

    2

    8

    12

    1

    6

    7

    11

    9

    6

    4

    10

    3

    12

    1

    2

    11

    8

    7

    5

    5

    4

    5

    7

    2

    10

    7

    10

    10

    2

    0

    6

    25

    6

    25

    49

    4

    100

    49

    100

    100

    4

    0

    36

     

    $$n=12,\quad \sum d^2=508$$

    $$r=1-\cfrac{6\sum d^2}{n(n^2-1)}=1-\cfrac{6\times 508}{12(12^2-1)}=1-\cfrac{3048}{1716}=-0.77$$

    Since $$r<0,$$ we can say that a very good student of history is a very bad student in mathematics.

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