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Statistical Tools and Interpretation Test - 5

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Statistical Tools and Interpretation Test - 5
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  • Question 1
    1 / -0

    In a dataset with 100 observations, what percentile does the third quartile (Q3) represent?

    Solution

    The third quartile (Q3) represents the point in a dataset where 75% of the observations fall below it and 25% of the observations are above it. In a dataset of 100 observations, the 75th percentile corresponds to Q3, indicating that 75 observations are below this value and 25 observations are above it.

  • Question 2
    1 / -0

    The mean of 10 observations is 10 . All the observations are increased by \(10 \%\). The mean of increased observations will be:

    Solution

    When each observation is increased by \(10 \%\), it means each observation is multiplied by \(1+\frac{10}{100}=1.1\).

    So, if the mean of the original observations is 10 , after increasing each observation by \(10 \%\), the new mean will also increase by the same factor.

    Therefore, the new mean will be \(10 \times 1.1=11\).

  • Question 3
    1 / -0

    Consider the following frequency distribution and find out the arithmetic mean.

     Class - intervals  0-10  10-20  20-30  30-40
     Frequency  8 10 12  15 
    Solution

    First, we will calculate the sum of all the data points multiplied by their respective frequencies i.e. ∑fx 

    Class intervals Mid-values \((x)\) Frequency \((f)\) \(fx\)
    0-10 5 8 40
    10-20 15 10 50
    20-30 25 12 300
    30-40 35 15 525
        \(\sum f=45\) \(\sum fx=1015\)

    Now, we know that, 

    Arithmetic mean = \(\frac{\sum fx}{\sum f}= \frac{1015}{45}=22.55\)

  • Question 4
    1 / -0

    If \(\mathrm{k}(\) Median - Mode \()=\) Mean then \(\mathrm{k}\) is ?

    Solution

    As we know,

    \(\Rightarrow\) Mean - Mode =3 Mean - Median

    \(\Rightarrow\) Mean- Mode =3 Mean -3 Median

    \(\Rightarrow\) 3 Median - Mode = 2 Mean

    \(\Rightarrow\) \(\frac{1}{2}\)(3 Median -  Mode) = Mean

    \(\therefore\) \(\mathrm{k}=\frac{1}{2}\)

  • Question 5
    1 / -0

    Which of the following is not related to the measure of central tendency?

    Solution

    Standard deviation is not a measure of central tendency. A measure of central tendency is a typical value for a probability distribution. The measures of central tendency, such as the mean, median, and mode, are used to describe the center or typical value of a dataset.

    Standard deviation measures the dispersion or spread of a dataset around the mean. It quantifies the average distance of data points from the mean. It provides information about the variability or scatter of the data points.

  • Question 6
    1 / -0

    The weighted arithmetic mean of the first n natural numbers whose weights are equal to the corresponding numbers is given by:

    Solution

    The first ' \(n\) ' natural numbers are \(1,2,3, \ldots . ., n\) and their corresponding weights are \(1,2,3, \ldots, n\)

    \(\therefore\) Weighted Mean\(=\overline{\mathrm{x}}_{\mathrm{w}}=\frac{\sum_{\mathrm{i}=1}^{\mathrm{n}} \mathrm{w}_{\mathrm{i}} \mathrm{x}_{\mathrm{i}}}{\sum_{\mathrm{i}=1}^{\mathrm{n}} \mathrm{w}_{\mathrm{i}}}\)

    \(\Rightarrow \frac{1 \times 1+2 \times 2+3 \times 3+ \ldots \ldots+\mathrm{n} \times \mathrm{n}}{1+2+3+\ldots \ldots+\mathrm{n}}\)

    \(\Rightarrow \frac{1^2+2^2+3^3+\ldots \ldots .+\mathrm{n}^2}{1+2+3+\ldots+\mathrm{n}}\)

    As sum of square of \(n\) natural numbers is \(=\frac{n(n+1)(2 n+1)}{6}\)

    \(\therefore\) mean \(=\frac{\frac{1}{6} \mathrm{n}(\mathrm{n}+1)(2 \mathrm{n}+1)}{\frac{1}{2} \mathrm{n}(\mathrm{n}+1)}\)

    \(\therefore\) mean \(=\frac{1}{3}(2 \mathrm{n}+1)\)

  • Question 7
    1 / -0

    Find the mode of the given set;

    \(3,5,9,6,5,9,2,9,3, 5\)

    Solution

    Mode = No. of element which is repeated more.

    Mode \(=5\) and 9

    \(\because\) Both are repeated 3 times in the series.

  • Question 8
    1 / -0

    Which of these is not affected by extreme values?

    Solution

    Median is the middle most value of a given series that represents the whole class of the series. So since it is a positional average, it is calculated by observation of a series and not through the extreme values of the series which. Therefore, median is not affected by the extreme values of a series.

  • Question 9
    1 / -0

    The average (arithmetic mean) of a set of seven numbers is 8. When an eighth number is added to the set, the average of the eight numbers is still 8. What number was added to the set?

    Solution

    If the average of a set of seven numbers is 8 , then the sum of these seven numbers is

    \(7 \times 8=56\)

    When the eighth number is added to the set, making it a total of eight numbers, and the average remains 8 , it means the sum of the eight numbers is still \(8 \times 8=64\).

    Number added \(=\) Sum of eight numbers - Sum of seven original numbers

    Number added \(=64-56\)

    So, the number added \(=8\)

  • Question 10
    1 / -0

    If the median (Q2) of a dataset is 50, what is the likely range of values for the first quartile (Q1) and third quartile (Q3) in a symmetric distribution?

    Solution

    In a symmetric distribution, such as a normal distribution, the median (Q2) is the midpoint of the dataset. If the median is 50, it means that 50% of the observations are below 50 and 50% are above 50. Similarly, in a symmetric distribution, the first quartile (Q1) would be the midpoint of the lower 50% of the data, which is 25, and the third quartile (Q3) would be the midpoint of the upper 50% of the data, which is 75. Therefore, the likely range of values for Q1 and Q3 in this case would be Q1 = 25 and Q3 = 75.

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