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Sets Test - 16

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Sets Test - 16
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  • Question 1
    1 / -0
    In a community of $$  175$$ persons, $$40$$ read TOI, $$50$$ read the Samachar Patrika and $$100$$ do not read either. How many persons read both the papers?
    Solution
    Number of people who read $$TOI$$ $$n(TOI)=40$$
    Number of people who read Samachar patrika, n(samachar patrika)$$=50$$
    Number of people who do not read newspaper$$=100$$
    Number of people who read newspaper $$(A\cup B)=$$Total number of people - people who don't read newspaper
    $$=175-100=75$$
    Number of persons who read both newspapers,
    $$n\left( A\cap B \right) =n\left( A \right) +n\left( B \right) -n\left( A\cup B \right) $$
    $$ n\left( A\cap B \right) =40+50-75$$
    $$n\left( A\cap B \right) =90-75=15$$
    Number of persons who read both newspapers$$=15$$
  • Question 2
    1 / -0
    If $$S$$ and $$T$$ are two sets such that $$S$$ has $$21$$ elements, $$T$$ has $$32$$ elements and $$\displaystyle S\cap T$$ has $$11$$ elements, then
    find the number of elements in $$\displaystyle S\cup  T$$.
    Solution
    Given $$n(S) = 21$$, $$n(T) = 32,$$ $$n$$($$\displaystyle S\cap T$$) $$= 11$$
    Now $$n(S) + n(T) =  n($$ $$\displaystyle S\cap T$$) $$+ n( $$$$\displaystyle S\cup  T$$)
    $$\displaystyle \Rightarrow $$ $$n($$ $$\displaystyle S\cup  T$$$$)  = 21 + 32 - 11  = 42  $$.
  • Question 3
    1 / -0
    In any continuous class interval table (a-b)
    Solution
    a is included b is included in the next interval
  • Question 4
    1 / -0
    Given $$P(A \cup B)=0.6, P(A\cap B)=0.2$$, the probability of exactly one of the event occurs is
    Solution
    Given, $$P(A\cup B)=0.6, P(A\cap B)=0.2$$
    Probability of exactly one of the event occurs is $$P(\bar{A}\cap B)+P(A\cap \bar{B})$$
    $$=P(B)-P(A\cap B)+P(A)-P(A\cap B)$$
    $$=P(A\cup B)+P(A\cap B)-2P(A\cap B)$$
    $$[\because P(A\cup B)=P(A)+P(B)-P(A\cap B)]$$
    $$=P(A\cup B)-P(A\cap B)$$
    $$=0.6-0.2$$
    $$=0.4$$
  • Question 5
    1 / -0

    Directions For Questions

    $$\mu = \left \{a, b, c, d, e, f, g, h, i, j\right \}$$
    $$P = \left \{a, b, c, e\right \}$$
    $$Q = \left \{b, c, d, f\right \}$$ and
    $$R = \left \{c, f, h, i, j\right \}$$
    Find the number of elements of the set

    ...view full instructions

    $$P\cap Q\cup R$$
    Solution
    $$ P = \left \{ a,b,c,e \right \} $$
    $$ Q = \left \{ b,c,d,f \right \} $$
    $$ \Rightarrow (P\cap Q) = \left \{ b,c \right \} $$
    As $$ R = \left \{ c,f,h,i,j\right \} $$
    $$ \Rightarrow \boxed {(P\cap Q)\cup R = \left \{ b,f,h,i,j \right \}} $$ 

  • Question 6
    1 / -0
    If $$A, B$$ and $$C$$ are any three set, then $$A \cup (B\cap C) =$$

    Solution
    Using distributive law of sets option B is correct
     Or it is the distributive law itself
  • Question 7
    1 / -0

    Directions For Questions

    $$\mu = \left \{a, b, c, d, e, f, g, h, i, j\right \}$$
    $$P = \left \{a, b, c, e\right \}$$
    $$Q = \left \{b, c, d, f\right \}$$ and
    $$R = \left \{c, f, h, i, j\right \}$$
    Find the number of elements of the set

    ...view full instructions

    $$(P\cap Q)\cup (Q\cap R)$$
    Solution
    $$ P = \left \{ a,b,c,e \right \};Q = \left \{ b_{n}c_{n}d_{n}f \right \} $$
    $$ \Rightarrow (P\cap Q) = \left \{ b,c \right \} $$
    As $$ R = \left \{ c,f,n,i,j \right \} \Rightarrow (Q\cap R) = \left \{ c,f \right \} $$
    $$ \boxed { (P\cap Q)\cup (Q\cap R) = \left \{ b,c,f \right \}} $$ 

  • Question 8
    1 / -0
    In a school with an envolment of $$950$$ students, each student must join either the lions club or the country club or both. Given that $$646$$ students are members of the lions club and $$532$$ are members of the country club, calculate the number of students who are members of both clubs
    Solution
    Total number of students $$=950$$
    Number of students who are members of lion club $$=646$$
    Number of students who are members of country club $$=532$$
    Number of students who are members of both club $$=(646+532)-950$$
                                                                                           $$=1178-950$$
                                                                                           $$=228$$
    $$\therefore$$  There are $$228$$ students who joined both clubs.
  • Question 9
    1 / -0

    Directions For Questions

    If $$A = \left \{2, 3, 4, 5\right \}, B = \left \{1, 3, 4, 5, 6\right \}, C = \left \{1, 3, 4, 5, 7, 8\right \}$$ and $$\cup = \left \{1, 2, 3, 4, 5, 6, 7, 8\right \}$$, then find

    ...view full instructions

    $$A - (B\cup C)$$
    Solution
    $$ (B\cup C) = \left \{ 1,3,4,5,6,7,8 \right \} $$
    $$ \therefore A - (B\cup C) = \left \{ 2 \right \}\begin{bmatrix} \because 3,4,5\,are\\present\,in\,B\cup C \end{bmatrix}$$

  • Question 10
    1 / -0
    If A and B be two sets containing $$4$$ and $$8$$ elements respectively, what can be the maximum number of elements in $$A\cup B$$? Find also, the minimum number of elements in $$(A\cup B)$$?
    Solution
    $${\textbf{Step -1: Find maximum number of elements.}}$$
                      $${\text{Given,}}$$
                      $$n(A) =4$$
                      $$n(B) =8$$
                      $${\text{Minimum number of elements in}}$$ $$A\cup B=8.$$
                      $${\text{A is subset of B.}}$$
                      $${\text{Maximum number of elements in}}$$ $$A\cup B=4+8=12.$$
                      $${\textbf{[All element taken in both set A and B and elements in both sets are different.]}}$$
    $${\textbf{Hence , maximum number of elements in}}$$ $$\mathbf{(A \cup B) =12.}$$
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