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Sets Test - 21

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Sets Test - 21
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  • Question 1
    1 / -0
    The number of subsets of the set $$A=\{ { a }_{ 1 },{ a }_{ 2 },.........{ a }_{ n }\} $$ which contain even number of elements is
    Solution
    The total no of subsets of $$A$$ is the cardinality of the power set of $$A$$. 

    So, if $$|A|=n$$ then $$|P(A)|=2^n$$. 

    Therefore total no of subsets of $$A$$ is $$2^n$$.

    Similarly,

    The even number of events is given by, $$2^{n-1}$$
  • Question 2
    1 / -0
    Let $$S=\{2,4,6,8,......20\}$$. What is the maximum number of subsets does $$S$$ have ?
    Solution
    Given,

    $$S={2,4,6,8........,20}$$

    There are a total of $$10$$ elements.

    Therefore we have $$2^{10}=1024$$ subsets.
  • Question 3
    1 / -0
    Which of the following collections is a set?
    Solution
    Collection of all months of a year is a set If we denote the given set, then 
    $$A =\{\text{January, February, March, April, ........December}\}$$
  • Question 4
    1 / -0
    For sets $$\phi  , A = \left \{ 1,3 \right \} = B = \left \{ 1, 5, 9 \right \} , C = \left \{ 1, 5, 7, 9 \right \}$$ True option is 
    Solution
    Option (B) is correct , because all the elements of set $$B = \left \{  1, 5, 9 \right \}$$ is present in set $$ C = (1, 5, 7, 9) $$ Hence , $$ B \subset  C $$
  • Question 5
    1 / -0
    If  $$ A = \left \{ 2 , 4, 6, 8 \right \} $$ and $$ B = \left \{ 1, 4, 7, 8 \right \}$$ then A - B and B - A will be respectively:
    Solution
    $$ A = \left \{ 2 , 4, 6, 8 \right \}$$ and $$ B = \left \{ 1, 4, 7, 8 \right \}$$
    $$ A - B = \left \{ 2, 6 \right \} $$ and $$ B - A = \left \{ 1 , 7 \right \}$$
    Hence , option (A) is correct
  • Question 6
    1 / -0
    If  $$ A = \left \{ 1, 2, 3, 4, 5, 6 \right \} , B = \left \{ 2, 4, 6, 8 \right \}$$, then A - B will be : 
    Solution
    Given , $$ A = \left \{ 1, 2, 3, 4, 5, 6 \right \}$$ and $$ B = \left \{2, 4, 6, 8  \right \}$$
    A - B means A contains the element which is not present in B. 
    Thus, $$A - B = \left \{ 1, 3, 5 \right \}$$
    Hence , option (B) is correct.
  • Question 7
    1 / -0
    If $$A= $${1,2,3};$$ B=$${4,5}. then $$A-B=$${1,2,3}  number cancellation of numbers in A and B
    Solution

  • Question 8
    1 / -0
    In an examination, $$34\%$$ of  the candidates fail in Arithmetic and $$42\%$$ in  English. If $$20\%$$ fail in Arithmetic and English, the  percentage of those passing in both subjects is :
    Solution
    Let $$A$$ denote students fail in Arithmetic, $$B$$ denote students fail in English
    $$n(A)=34$$
    $$n(B)=42$$
    $$n(A \cap B)=20$$
    $$n(A \cup B) = n(A) + n(B) - n(A \cap B) = 34+42-20=56$$
    $$n(A \cup B)' = 100 - n(A \cup B) = 100-56=44$$
  • Question 9
    1 / -0
    The smallest set $$A$$ such that $$A\cup \left\{ 1,2 \right\} =\left\{ 1,2,3,5,9 \right\} $$ is 
    Solution
    $$A\cup \{1,2\}=\{1,2,3,5,9\}$$
    Thus 
    $$A=\{1,2,3,5,9\}-\{1,2\}$$

    Hence 
    $$A=\{3,5,9\}$$
  • Question 10
    1 / -0
    If A = {1, 2, 3} B = {4, 5}, then find A - B.
    Solution
    Given, $$A=\{1,2,3\}$$ and $$B=\{4,5\}$$.
    Since $$A$$ and $$B$$ are two disjoint sets i.e. $$A\cap B=\phi$$ then we've,
    $$A-B$$
    $$=\{1,2,3\}$$.
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