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Statistics Test - 12

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Statistics Test - 12
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Weekly Quiz Competition
  • Question 1
    1 / -0
    A child says that the median of $$3, 14, 18, 20, 5$$ is $$18$$. What concept does the child missed about finding the median?
    Solution
    To calculate the median of any data series. The data series has to be arranged in the ascending order. The child hasn't arranged the data series in ascending order.
  • Question 2
    1 / -0
    The mean deviation of the data $$2,9,9,3,6,9,4$$ from the mean is
    Solution
     Given data is, 2,9,9,3,6,9,4
    Here, $$\displaystyle n = 7, \bar{x}=\frac{2+9+9+3+6+9+4}{7}=6$$
    $$\therefore$$ Mean deviation from mean is $$=\displaystyle \frac{1}{n}\left(\sum |x-\bar{x}|\right)=\frac{4+3+3+3+0+3+2}{7}=\frac{18}{7}=2.57$$
  • Question 3
    1 / -0
    Mode of $$2, 3, 4, 5, 0, 1, 3, 3, 4, 3\ is\ 3.$$
    Solution
    Mode is the term which appears maximum number of times.

    The terms are: 2, 3, 4, 5, 0, 1, 3, 3, 4, 3
    Arranging them in ascending order: 0,1,2,3,3,3,3,4,4,5
    3 is occurring maximum number of times. hence mode is 3.
  • Question 4
    1 / -0
    Which one of the following statements is correct ?
    Solution
    We know $$Variance(\sigma^2)=\dfrac{\sum(x-\overline{x})^2}{n}$$
    Where,
    $$\sigma^2$$ is variance
    $$\overline{x}$$ is mean
    $$n$$ is number of observations.
    Standard deviation $$(\sigma)=\sqrt{\dfrac{\sum(x-\overline{x})^2}{n}}$$
    $$\therefore$$  We can see, the standard deviation for a given distribution is the square root of the variance.
  • Question 5
    1 / -0
    The mean of $$x + 3, x + 5, x + 7, x + 9$$ and $$x + 11$$ is
    Solution
    The observations are : $$x+3,x+5,x+7,x+9, x+11$$
    Mean = $$\dfrac{sum}{number \quad of \quad observations}$$ = $$\dfrac{x+3,x+5,x+7,x+9, x+11}{5}$$ = $$\dfrac{5x + 35}{5} = x + 7$$
  • Question 6
    1 / -0
    A student got marks in $$5$$ subjects in a monthly test is given below: $$2, 3, 4, 5, 6$$.
    In these obtained marks, $$4$$ is the
    Solution
    Marks obtained $$= 2,3,4,5,6$$

    Median is the middle term $$= 4$$.
    Mean $$= \dfrac{2+3+4+5+6}{5} = 4$$.
  • Question 7
    1 / -0
    Coefficient of deviation is calculated by the formula:
    Solution
    It is a fundamental concept.
    coefficient of deviation $$=\cfrac{\sigma}{\bar{x}}\times 100$$
    where $$\sigma$$ and $$\bar{x}$$ are standard deviation and mean respectively.
  • Question 8
    1 / -0
    The marks of $$20$$ students in a test were as follows:
    $$5, 6, 8, 9, 10, 11, 11, 12, 13, 13, 14, 14, 15, 15, 15, 16, 16, 18, 19, 20$$
    The mode is
    Solution
    Terms are: $$5, 6, 8, 9, 10, 11, 11, 12, 13, 13, 14, 14, 15, 15, 15, 16, 16, 18, 19, 20$$.
    $$15$$ occurs most number of times $$(3$$ times$$)$$. 
    Hence, $$15$$ is the mode of the marks.
  • Question 9
    1 / -0
    The mean deviation about median from the data
    $$340,150,210,240,300,310,320$$ is
    Solution
    Arrange in increasing order
    150,210,240,300,310,320,340           N=number of data = 7
    median (M) =300
    The mean deviation about median $$=  \frac{150+90+60+0+10+20+40}{7 }= 52.857$$
  • Question 10
    1 / -0
    Find the mode of:
    Height ($$cm$$)
    $$37$$
    $$38$$
    $$39$$
    $$40$$
    $$41$$
    Number of plants$$46$$
    $$89$$
    $$93$$$$90$$
    $$153$$
    Solution
    mode $$=41$$ (highest frequency $$= 153$$)
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