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Probability Test - 10

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Probability Test - 10
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  • Question 1
    1 / -0
    There are $$30$$ tickets numbered from $$1$$ to $$30$$ in a box . A ticket is drawn at random. What is the probability that the ticket drawn bears an odd number?
    Solution
    Total number of outcomes $$= 30$$
    Favourable outcomes (odd number on the ticket) $$= 15$$
    Probability $$=\dfrac{15}{30} = \dfrac{1}{2}$$
  • Question 2
    1 / -0
    The probability of an impossible event is ____
    Solution
    Probability of event in $$E$$, $$ P\left( E \right) =\dfrac { \text {number of events in E} }{ \text {Total number of possible events}} $$
    If the desirable event does not happen even once, then the numerator in the above formula becomes equal to zero. 
  • Question 3
    1 / -0
    Suppose six coins are flipped. Then the probability of getting at least one tail is:
    Solution
    Total number of events that would occur by flipping six coins
    $$=2^6=64.$$
    Probability that no tail occurs $$=\dfrac {1}{64}$$
    Probability of occurring at least one tail$$=1-\dfrac {1}{64}=\dfrac {63}{64}$$
  • Question 4
    1 / -0
    In tossing a coin, the chance of throwing head and tail alternatively in $$3$$ successive trials is
    Solution
    Favourable outcomes $$= \{HTH,THT\}= 2$$ outcomes
    Total number of outcomes $$= 8$$
    Probability $$=$$ $$\dfrac{2}{8}$$ $$=$$ $$\dfrac{1}{4}$$
  • Question 5
    1 / -0
    A die is thrown then find the probability of getting an odd number.
    Solution
    Sample space $$= {1,2,3,4,5,6}$$
    odd nos. $$= 1,3,5$$
    probability of getting odd nos.$$=\cfrac{3}{6}$$ $$=\cfrac{1}{2}$$
  • Question 6
    1 / -0
    If $$P(A) = P(B)$$, then the two events $$A$$ and $$B$$ are -
    Solution
    Events are said to be equally likely if there is no preference for a particular event over the other.

    Examples

    When a coin is tossed, Head (H) or Tail is equally likely to occur.
    If $$P(A)=P(B),$$ then the two events A and B are equally likely

  • Question 7
    1 / -0
    If the events $$A$$ and $$B$$ be mutually exclusive, then $$P(A+B)$$ will be equal to
    Solution
    For mutually exclusive events A and B, we have
    $$\displaystyle A\cap B= \phi $$ so that $$\displaystyle P\left ( A\cap B \right )= 0.$$ So in this case, we have
    $$\displaystyle P\left ( A\cup B \right )$$ or $$\displaystyle P\left ( A+B \right )= P\left ( A \right )+P\left ( B \right ).$$
  • Question 8
    1 / -0
    If two coins are tossed then find the probability of the event that at least one tail turns up is:
    Solution
    2 coins tossed sample space $$= {(h,h),(h,t),(t,h),(t,t)}$$
    Number of outcomes that have atleast one tail $$= 3 $$
    probability is $$\cfrac{ 3}{4}$$
  • Question 9
    1 / -0
    All possible outcomes of a random experiment forms the -
    Solution
    Sample Space is the set of all possible outcomes of an experiment. It is denoted by S.
    Examples:
    When a coin is tossed, S = {H, T} where H = Head and T = Tail
    When a dice is thrown, S = {1, 2 , 3, 4, 5, 6}
    When two coins are tossed, S = {HH, HT, TH, TT} where H = Head and T = Tail
  • Question 10
    1 / -0
    The sum of the probabilities of all the elementary events of an experiment is ____?
    Solution
    The probability $$p$$ of any event must be greater than or equal to $$0$$. 
    In other words, $$0 \leq p \leq 1$$. 
    Since $$1$$ is the maximum limit, all probabilities must add to $$1$$.
    Hence, the sum of the probabilities of all the elementary events of an experiment is $$1$$. 
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