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Probability Test - 13

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Probability Test - 13
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  • Question 1
    1 / -0
    Write the sample space when a coin is tossed.
    Solution
    When a coin is tossed, there are two possible outcomes: a head ($$H$$) or a tail ($$T$$). The sample space of this experiment is $$S = [H, T]$$
  • Question 2
    1 / -0
    If a card is drawn from a pack of cards. The probability of getting black ace is
    Solution
    Total number of cases $$= 52$$
    Number of favourable cases (getting a black ace) $$= 2$$
    Thus, Probability (getting a black ace) $$=$$ $$\cfrac{2}{52} = \cfrac{1}{26}$$
  • Question 3
    1 / -0
    Two dice are thrown simultaneously. Find the probability of getting an even number as the sum.
    Solution
    Total number of possible cases $$= 36$$
    Favourable cases of getting even number as the sum
    $$= \{(1, 1), (1,3), (1,5), (2, 2), (2, 4), (2, 6), (3, 1), (3, 3), (3,5), (4, 2), (4,4), (4,6), (5,1), \ \ \  \ \\ \ \ \ \ \ \  (5, 3), (5, 5), (6, 2), (6,4),\ (6, 6)\}$$
    Total number of favourable cases $$= 18$$
    $$P $$(getting even number as the sum) $$=$$ $$\displaystyle \frac{18}{36} = \frac{1}{2}$$
  • Question 4
    1 / -0
    If $$P(E) =0.05$$, then $$P($$not $$E) =$$
    Solution
    We know that, $$0≤$$ Probability $$≤1$$
    $$P(E) = 0.05$$
    $$P ($$not $$E) = 1- P(E)$$
    $$P($$not $$E) = 1- 0.05 = 0.95$$
  • Question 5
    1 / -0
    When a die is thrown, list the outcomes of an event of getting:
    I. A prime number,
    II. Not a prime number.
    Solution
    In a throw of die, the total outcomes are $$\{1,2,3,4,5,6\}$$
    (a) A prime number are $$2,3$$ and $$5$$.
    (b) Not a prime number are $$1, 4$$ and $$6$$.
    Hence the answer is option A
  • Question 6
    1 / -0
    The probability of _____ event is 0.
    Solution
    The probability of an impossible event is 0.
  • Question 7
    1 / -0
    Two dice are thrown simultaneously. Find the probability of getting a multiple of 2 on first dice and a multiple of 3 on the second dice.
    Solution
    Total cases = $$6\times 6$$
    Let A be the event of getting a multiple of  2 on first dice and a multiple of 3 on the second dice.
    Hence, $$A= \{(2,3),(2,6),(4,3),(4,6),(6,3),(6,6)\}$$
    $$n(A) =$$ $$6$$
    $$\therefore $$ $$P(A) =$$ $$ \dfrac 6{36} = \dfrac 16 $$
    $$\therefore $$ Option C is correct.
  • Question 8
    1 / -0
    The probability of ____ event is 1.
    Solution
    The probability of a sure event is 1.
  • Question 9
    1 / -0
    One coin is tossed once. Find the probability of getting A head.
    Solution
    The outcome of a throw of coin can be $$2$$.
    $$P($$head$$)=$$$$\dfrac{1}{2}$$
  • Question 10
    1 / -0
    A bag contains $$4$$ red balls, $$6$$ blue balls and $$3$$ black balls. A ball is draw at random from the bag. What is the probability that the ball drawn is not blue?
    Solution
    Total no. of balls$$=4+6+3=13$$
    Total number of ways drawing one ball out of 13, n(S)$$=13C_1$$
    No.of ways of drawing 1 ball,none of then is blue,n(E)$$=^{13- 6}C_1=^7C_1$$
    $$\therefore  probability=\dfrac{n(E)}{n(S)}=\dfrac{7}{13}$$
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