Probability Test

Result

Probability Test - 3

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

The letters of the word ‘ASSASSIN ‘ are written at random in a row. The chance that all the similar letters occur together is

A
1/ 14

B
34/ 35

C
1/ 35

D
none of these

Solution

4!/{8!/2!4!}=1/35
Question 2
1 / -0

Let A be set of 4 elements. From the set of all functions from A to A, a function is chosen at random. The chance that the selected function is an onto function is

A
3/ 32

B
1/ 64

C
29/ 32

D
none of these

Solution

No. of function from A to A = 4⁴

No. of onto function from A to A = 4!

∴ Required probability =4!/4⁴= 3/32
Question 3
1 / -0

Both A and B throw a dice. The chance that B throws a number higher than that thrown by A is

A
21/ 36

B
13/36

C
15/ 36

D
1/ 2

Solution

Total possible ways of getting number in B's dice throw greater that A's dice throw are

{(1,2) , (1,3) , (1,4) , (1,5) , (1,6) , (2,3) , ( 2,4) , (2,5) , (2,6) , (3,4) , (3,5) , (3,6) , (4,5) , (4,6) , (5,6)} = 15

Total number of elements in the sample space = 6X6 = 36

Therefore P(probability of B is greater than A) = 15/36
Question 4
1 / -0

Both A and B throw a dice. The chance that B throws a number not less than that thrown by A is

A
1/ 2

B
15/ 36

C
19/36

D
21/ 36

Solution

Given B getting number not less than A means B can get number on dice greater than or equal to A.

For throwing A and B one dice, the number of elements in the sample space is 6x6=36 i.e. n(S)= 36

Let E be the event of "B getting number not less than A", So it can happen in 21 ways out of 36 ways.

The ways are E={(1,1), (1,2),(1,3), (1,4), (1,5), (1,6), (2,2), (2,3), (2,4),(2,5),(2,6),(3,3),(3,4),(3,5),(3,6),(4,4),(4,5),(4,6),(5,5),(5,6),(6,6)} i.e. n(E)= 21

Therefore, P(E)= n(E)/n(S) = 21/36
Question 5
1 / -0

Two dice are thrown. The number of sample points in the sample space when 6 does not appear on either dice is

A
18

B
30

C
25

D
11

Solution

total no. of outcomes=6²=36

The pair which shows 6 on either dice are {(6,1),(6,2),(6,3),(6,4),(6,5),(1,6),(2,6),(3,6),(4,6),(5,6),(6,6)}=11

So total number of sample points in sample space when 6 on either dice do not appear=36-11=25
Question 6
1 / -0

A dice is rolled 6 times. The probability of obtaining 2 and 4 exactly three times each is

A
5/ 11664

B
1/ 5184

C
1/ 46656

D
none of these

Solution

Total ways of getting 2 and 4 exactly 3 times is 6! / (3! 3!) = 20

Total number of ways in throwing 6 dice is 6⁶

Therefore probability is 20/ 6⁶ = 5/11664
Question 7
1 / -0

A dice has 3 faces each bearing ‘ 2 ‘ and three faces each bearing ‘ 6 ‘. It is rolled once. The probability of showing up ‘a six ‘ is

A
1

B
1/ 6

C
1/2

D
none of these

Solution

Total no. of outcomes = 6={2,2,2,6,6,6}

p(getting a six)=3/6=1/2

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Probability Test - 3

Result

Probability Test - 3

Score

-

Rank

-

SHARING IS CARING

Question 1

1/ 14

34/ 35

1/ 35

none of these

Solution

Question 2

3/ 32

1/ 64

29/ 32

none of these

Solution

Question 3

21/ 36

13/36

15/ 36

1/ 2

Solution

Question 4

1/ 2

15/ 36

19/36

21/ 36

Solution

Question 5

18

30

25

11

Solution

Question 6

5/ 11664

1/ 5184

1/ 46656

none of these

Solution

Question 7

1

1/ 6

1/2

none of these

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.