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Relations and Functions Test - 3

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Relations and Functions Test - 3
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Which of the following statement is false?

    Solution

    The total number of relations that can be defined from a set A to set B is the number of possible subsets of A ´ B.

    If n(A) = m and n(B) = n, then the number of relations from A to B = 2mn.

     

  • Question 2
    1 / -0

    If f(x) = x2 and g(x) = x are two functions from R to R then (fg)(2) is

    Solution

    fg(2 )=  f(2).g(2) = 22.2 = 8

     

  • Question 3
    1 / -0

    Let A = {1, 2, 3, …, 30} and R be the relation “is one-fifth of”  on A. Then the range of R is

    Solution

    The range of the relation R is the set of all second elements of the ordered pair in a relation R. Here R = {(1, 5), (2, 10), (3, 15), (4, 20), (5, 25), (6, 30)}

    Range is {5, 10, 15, 20, 25, 30}

     

  • Question 4
    1 / -0

    If n(A)=2, n(B)=2 . What is the total number of relations from A to B?

    Solution

    The number of relations from a set with m elements to a set with n elements is given by 2m.n

    Hence, No. of relations from A to B is 22x2 = 16

     

  • Question 5
    1 / -0

    A={1, 2, 3, 4, …, 14}. Let R be a relation from A to A defined by

    R = {(a, b):3a – b = 0, a, b∈ A} then domain of R is

    Solution

    Here (a, b) ∈ R, 3a = b,

    Therefore

    R = {(1, 3), (2, 6), (3, 9), (4, 12)}

    Domain of relation R is the set of I elements of the ordered pairs 

    Domain R= {1, 2, 3, 4}

     

  • Question 6
    1 / -0

    Find the domain of the function f(x) = x |x|

    Solution

    Domain of the function f is all real numbers. Since f(x) =x|x| is defined for all real values of x .

     

  • Question 7
    1 / -0

    If ordered pair (a + 2b, 9) = (7, 3a + 2b), then the values of a and b are

    Solution

    Two ordered pairs are equal, if and only if the corresponding first elements are equal and the second elements are also equal.

    Hence, a + 2b = 7 and 3a + 2b = 9.

    Solving the linear equations, we get

    a = 1 and b = 3

     

  • Question 8
    1 / -0

    Which of the relations is not a function?

    Solution

    For a relation to be a function one element of the domain must not be connected with more than one elements of the co-domain. Hence the answer.

     

  • Question 9
    1 / -0

    The graph of f(x) = x2 lies in:

    Solution

    In the graph of f(x) = x2, f will take only positive values. Hence graph will lie above x-axis. Hence, 1st and 2ndquadrant.

     

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