Trigonometric F...

sin (180+ϕ) sin(180−ϕ) cosec²ϕ

The solution of equation $$\cos^2 \theta +\sin \theta+1=0$$ lies in the interval

In which quadrant does the terminal side of the angle $$250^0$$ lie?

In which quadrant does the terminal side of the angle $$330^0$$ lie?

The minimum value of $$ \displaystyle  \sec ^{2}\alpha + \cos ^{2}\alpha   $$ is 

$$\cfrac { \tan { \theta  }  }{ \sec { \theta  } -1 } +\cfrac { \tan { \theta  }  }{ \sec { \theta  } +1 } $$ is equal to

If $$\sin { \theta  } +\cos { \theta  } =p$$ and $$\tan { \theta  } +\cot { \theta  } =q$$, then $$q\left( { p }^{ 2 }-1 \right) =$$

$$\cfrac { 1 }{ \sec { \theta  } -\tan { \theta  }  } $$ is equal to

If $$\tan\theta +\cot\theta =2$$, then the value of $$\tan^2\theta +\cot^2\theta$$ is __________?

$$\cos ^{ 4 }{ A } -\sin ^{ 4 }{ A } $$ is equal to

If $$\alpha $$ and $$\beta $$ are two different solution lying between $${{ - \pi } \over 2}$$ and $${\pi  \over 2}$$ of the equation $$2{\mathop{\rm Tan}\nolimits} \theta  + {\mathop{\rm Sec}\nolimits} \theta  - 2$$ then $${\mathop{\rm Tan}\nolimits} \alpha  + {\mathop{\rm Tan}\nolimits} \beta $$ is