Complex Numbers...

The argument of the complex number $$\sin \dfrac {6\pi}{5}+i\left(1+\cos \dfrac {6\pi}{5}\right)$$ is

Let $$a, b, c\epsilon R_{0}$$ and $$1$$ be a root of the equation $$ax^{2} + bx + c = 0$$, then the equation $$4ax^{2} + 3bx + 2c = 0$$ has

If z is a complex number such that $$|z|\ge 2$$, then the minimumm value of $$\left|z+\dfrac{1}{2}\right|$$:

The complex no. $$\dfrac{1+2i}{1-i}$$ lies in which quadrant of the complex plane

If $$z \neq 0$$, then $$ \overset{100}{\underset{0}{\int}}arg(-|z|)dx =$$

If $$z$$ is purely real and $$Re(z)<0$$, then $$arg(x)$$ is

In Argand diagram, O, P, Q represents the origin, $$z$$ and $$z+iz$$
respectively. then $$\angle OPQ = $$

If $$Z$$ is a complex number such that $$|z| \ge 2$$,
then the minimum value of $$\left|z + \dfrac{1}{2}\right|$$

If $$\left| {\dfrac{{{z_1}}}{{{z_2}}}} \right| = 1$$ and $$\arg \left( {{z_1}{z_2}} \right) = 0$$ , then

If $$|z|=1$$ and $$|\omega -1| =1$$ where $$z, \omega \in C$$, then the largest set of values of $$|2z - 1|^2 + | 2\omega -1|^2$$ equals