Mechanical Properties of Fluids Test

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Mechanical Properties of Fluids Test - 7

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Weekly Quiz Competition

Question 1
1 / -0

Soldering of two metals possible because of the property of

A
surface tension

B
osmosis

C
viscosity

D
cohesion

Solution

Cohesion is the attractive force among the same kind of materials. Thus soldering of two metals is possible due to cohesion.
Question 2
1 / -0

If a block of iron of unknown mass of size 5 cm × 5 cm × 5 cm was completely submerged in water, what is the mass of block. (density of water = 1 gm/ cm³)

A
80 gm

B
90 gm

C
125 gm

D
100 gm

Solution

When it is submerged completely its weight will be balanced by the buoyant force which is equal to the mass of water displaced. Thus let mass of block be m then at equilibrium

mg=Vρg

m=5×5×5×1

m=125 gm
Question 3
1 / -0

A boy is carrying a bucket of water in one hand with a 0.05 kg cork piece in it. After sometime he takes out the cork piece and holds it in the other hand. The boy will carry

A
Less load than before

B
More load than before

C
Either less or more load depending on the density of plastic

D
Same load as before

Solution

as there is no change in total weight only the place of the cork piece has change.
Question 4
1 / -0

A beaker is partly filled with water, the beaker and the contents have a mass of 50 gm. A piece of wood having a volume of 5 cc. is floated in the beaker. The density of wood is 0.8 g/cc. the mass of the beaker and its contents is

A
46 g

B
56.25 g

C
50 g

D
54 g

Solution

v=m/d

m=v*d (mass = density*volume)

total mass = 50+0.8*5 = 50+4 =54
Question 5
1 / -0

A bird, resting on the floor of an airtight box, which is being carried by a boy, starts flying. The boy will feel that the box

A
is now lighter

B
is now heavier

C
lighter in the beginning and heavier afterwards

D
shows no change in weight

Solution

If the cage is completely closed, it doesn't make a difference if the bird is hovering inside it or if it sits on the ground. When flying, the bird pushes air to the ground which will exert a downward force on the cage exactly equal to the weight of the bird. This is a direct consequence of the conservation of momentum and Newton's second & third law. Since no additional external force is acting on the cage-bird-system when the bird is flying as compared to when it's not, the acceleration on the cage can be no different. The effect due to the flying of bird only concerns the internal forces and since action=reaction, hence there is no change in the weight of the box.

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Re-Attempt Weekly Quiz Competition

Mechanical Properties of Fluids Test - 7

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Mechanical Properties of Fluids Test - 7

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SHARING IS CARING

Question 1

surface tension

osmosis

viscosity

cohesion

Solution

Question 2

80 ​​​gm

90 ​​​​gm

125 gm​​​​

100 ​​​​​​gm

Solution

Question 3

Less load than before

More load than before

Either less or more load depending on the density of plastic

Same load as before

Solution

Question 4

46 g

56.25 g

50 g

54 g

Solution

Question 5

is now lighter

is now heavier

lighter in the beginning and heavier afterwards

shows no change in weight

Solution

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80 gm

90 gm

125 gm

100 gm