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Thermal Properties of Matter Test - 22

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Thermal Properties of Matter Test - 22
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  • Question 1
    1 / -0
    A gas behaves more closely as an ideal gas at :
    Solution
    (B):
    Condition for gas to behave like ideal gas :

    (1) pressure should be lower so gases can move independently. 
    (2) The temperature should be high so that the kinetic energy of gases can overcome the interaction among molecules. 
    It satisfies the equation of state.
  • Question 2
    1 / -0
    The propagation of heat in vacuum takes place by
    Solution
    In vacuum there have no material medium. So Heat transfer only takes place by Radiation only.
  • Question 3
    1 / -0
    Which of the following carries anomalous expansion ?
    Solution
    (B)Water
    Anomalous expansion is from $$4^oc$$ to $$0^0c$$  which generally expected to be contraction for other liquid as we are moving from liquid to solid region  

  • Question 4
    1 / -0
    Thermal radiation are
    Solution
    All types of radiation produce electromagnetic wave with different wavelength. 
    Hence option: A
  • Question 5
    1 / -0
    Every gas (real gas ) behaves as an ideal gas 
    Solution
    Generally, a gas behaves more like an ideal gas at higher temperature and lower pressureas the potential energy due to intermolecular forces becomes less significant compared with the particles' kinetic energy, and the size of the molecules becomes less significant compared to the empty space between them.
  • Question 6
    1 / -0
    Absolute temperature can be calculated by
    Solution
    Absolute temperature is proption to Mean square velocity.
    and independent of motion of molecule.
    $$\overset{-}{v^2} \propto T$$
    Hence option A is correct
  • Question 7
    1 / -0

    A glass is full of water at $$4^{0}C$$ when it is (a) cooled (b) heated. Then, which one of the following is correct?

    Solution
    When heated above $$4^0$$C, volume will increase, hence it will overflow.
    When cooled below $$4^0$$C, it also expands and  volume increases( anomalous expansion) until $$0^0$$C.
    Hence, in both cases it will overflow.
  • Question 8
    1 / -0

    The graph between temperature and pressure of a perfect gas is

    Solution
    From ideal gas equation, PV = nRT
    so P-T curve at constant volume is a straight line.
    If the temperature is written in Kelvin, it turns out that the intercept is at 273
  • Question 9
    1 / -0

    The graph drawn between pressure and temperature at constant volume for a given mass of different molecular weights $$M_{1}$$ and $$M_{2}$$ are the straight lines as shown in the figure then 

    Solution
    From ideal gas equation, PV = nRT = $$\frac{w}{M}RT$$
    Slope of P-T curve = $$\frac{wR}{MV}$$
    Since V = constant and w = constant, we get that the slope is inversely proportional to molecular weight
    Steeper the line, more is slope, less is molecular weight.
    So, $$M_{1} > M_{2}$$
  • Question 10
    1 / -0

    All gasses deviate from gas laws at

    Solution
    At high pressure and low temperature, the molecular interaction terms become significant.
    So, we cannot neglect these terms.
    Also, the total size of molecules becomes significant at low temperatures.
    So, at low temperature and high pressure, there is a significant deviation from ideal gas equation.
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