Thermodynamics ...

A thermodynamics cycle takes in heat energy at a high temperature and rejects energy at a lower temperature. If the amount of energy rejected at the low temperature is 3 times the amount of work done by the cycle, the efficiency of the cycle is:

Monoatomic , diatomic and triatomic gases whose initial volume and pressure are same , are compressed till their volume becomes half the initial volume.

A reversible adiabatic path on a P-V diagram for an ideal gas passes through sate A where $$ P=0.7 \times 10^5 N/{m}^{-2} $$ and $$v=0.0049\ m^3$$. The ratio of specific heat of the gas is 1.4 . The slope of path at A is:

$$1\ kg $$ of gas does $$20\ kJ$$ of work and receives $$16\ kJ$$ of heat when it is expanded between two states. A second kind of expansion can be found between the initial and final state which requires a heat input of $$9\ kJ$$. The work done by the gas in the second expansion is:

On an isothermal process, there are two POINTs $$A$$ and $$B$$ at which pressures and volumes are $$(2P_o,\:V_o)$$ and $$(P_o,\:2V_o)$$ respectively. If $$A$$ and $$B$$ are connected by a straight line, the temperature of the isothermal process is how much lower the maximum temperature

A vessel contains an ideal monoatomic gas which expands at constant pressure, when heat $$Q$$ is given to it. What is the work done?

In an adiabatic process, $$\displaystyle R=\frac{2}{3}C_v$$. The pressure of the gas will be proportional to:

An ideal gas confined into an insulated chamber is allowed to enter into an evacuated insulated chamber. If Q,W and $$ \Delta E _{int} $$ have the usuak meanings, then

Certain perfect gas is found to obey $$ P{V} ^{3/2} = constant $$ during an adiabatic process. If such a gas at initial temperature T is adiabatically compressed to half the initial volume, its final temperature will be 

One mol of a gas at NTP is suddenly expanded to three times its initial volume. If $$C_v =2 R$$, the ratio of initial to final pressure of gas will nearly be