Thermodynamics Test

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Thermodynamics Test - 69

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Question 1
1 / -0

First law of thermodynamics is a special case of

A
Newton's law

B
law of conservation of energy

C
Charle's law

D
Law of heat exchange

Solution

The first law of thermodynamics states that: $$\Delta Q=\Delta U +\Delta W$$

Heat supplied goes into increasing internal energy and work done by gas.
Upon interpretation, we get the law of conservation of energy.
The first law of thermodynamics is based on the law of conservation of energy.
Question 2
1 / -0

Can two isothermal cures cut each other ?

A
Never

B
Yes

C
They will cut when temperature is $$0^{\circ}$$C

D
Yes, when the pressure is critical pressure

Solution

No, If they intersect, then at two different temperatures (of the isothermals), volume and pressure of gas will be same, which is not possible.
Question 3
1 / -0

First law thermodynamics stated that

A
System can do work

B
System has temperature

C
System has pressure

D
Heat is a from energy

Solution

The First Law of Thermodynamics states that heat is a form of energy, and thermodynamic processes are therefore subject to the principle of conservation of energy. This means that heat energy cannot be created or destroyed.
Question 4
1 / -0

If a cylinder containing a gas at high pressure explodes, the gas undergoes

A
Reversible adiabatic change and fall of temperature

B
Reversible adiabatic change and rise of temperature

C
irreversible adiabatic change and fall of temperature

D
irreversible adiabatic change and rise of temperature

Solution

Gas cylinder suddenly explodes is an irreversible adiabatic change and work done against expansion reduces the temperature.
Question 5
1 / -0

Which is the correct statement

A
For an isothermal change PV = constant

B
In an isothermal process the change in internal energy must be equal to the work done

C
For an adiabatic change $$\dfrac{P_{2}}{P_{1}} = \left ( \dfrac{V_{2}}{V_{1}} \right )^{\gamma }$$ where $$\gamma $$ is the ratio of specific heats

D
In an adiabatic process work done must be equal to the heat entering the system

Solution

From the ideal gas equation,
Since PV = RT and T = constant: PV constant .
Question 6
1 / -0

When heat is given to a gas in an isothermal change, the result will be

A
External work done

B
Rise in temperature

C
External in internal energy

D
External work done and also rise in temp.

Solution

When heat is given to a gas in an isothermal change, the result will be External work done and also rise in temp.
Question 7
1 / -0

When heat in given to a gas in an isobaric process, then

A
The work is done by the gas

B
Internal energy of the gas increases

C
Both (a) and (b)

D
None of these (a) and (b)

Solution

When heat is supplied at constant pressure, a part of it goes in the expansion of gas and remaining part is used to increase the temperature of the gas which in turn increases the internal energy .
Question 8
1 / -0

A container that suits the occurrence of an isothermal process should be made of

A
Copper

B
Glass

C
Wood

D
Cloth

Solution

An isothermal process takes place at constant temperature, must be carried out in vessel with conducting wall so that heat generated should go out at once.
Question 9
1 / -0

If $$\bigtriangleup Q$$ and $$\bigtriangleup W$$ represent the heat supplied to the system and the work done on the system respectively, then the first law of thermodynamics can be written as

A
$$\bigtriangleup Q = \bigtriangleup U + \bigtriangleup W$$

B
$$\bigtriangleup Q = \bigtriangleup U - \bigtriangleup W$$

C
$$\bigtriangleup Q = \bigtriangleup W - \bigtriangleup U$$

D
$$\bigtriangleup Q = -\bigtriangleup W - \bigtriangleup U$$

Solution

The first law of thermodynamics states that the change in internal energy of a system equals the net heat transfer into the system minus the net work done by the system. In equation form, the first law of thermodynamics is ΔU = Q − W. Here ΔU is the change in internal energy U of the system.
Question 10
1 / -0

In adiabatic expansion

A
$$\bigtriangleup U$$

B
$$\bigtriangleup U$$= negative

C
$$\bigtriangleup U$$ = positive

D
$$\bigtriangleup W$$ = zero

Solution

In case of adiabatic expansion
$$\Delta W = positive$$ and $$ \Delta Q = O $$
from FLOT
$$\Delta Q =\Delta U+\Delta w\Rightarrow \Delta U =-\Delta W $$ i.e $$ \Delta U $$ Will be negative .

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Thermodynamics Test - 69

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Thermodynamics Test - 69

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Question 1

Newton's law

law of conservation of energy

Charle's law

Law of heat exchange

Solution

The first law of thermodynamics states that: $$\Delta Q=\Delta U +\Delta W$$

Heat supplied goes into increasing internal energy and work done by gas.Upon interpretation, we get the law of conservation of energy.The first law of thermodynamics is based on the law of conservation of energy.

Question 2

Never

Yes

They will cut when temperature is $$0^{\circ}$$C

Yes, when the pressure is critical pressure

Solution

Question 3

System can do work

System has temperature

System has pressure

Heat is a from energy

Solution

Question 4

Reversible adiabatic change and fall of temperature

Reversible adiabatic change and rise of temperature

irreversible adiabatic change and fall of temperature

irreversible adiabatic change and rise of temperature

Solution

Question 5

For an isothermal change PV = constant

In an isothermal process the change in internal energy must be equal to the work done

For an adiabatic change $$\dfrac{P_{2}}{P_{1}} = \left ( \dfrac{V_{2}}{V_{1}} \right )^{\gamma }$$ where $$\gamma $$ is the ratio of specific heats

In an adiabatic process work done must be equal to the heat entering the system

Solution

Question 6

External work done

Rise in temperature

External in internal energy

External work done and also rise in temp.

Solution

Question 7

The work is done by the gas

Internal energy of the gas increases

Both (a) and (b)

None of these (a) and (b)

Solution

Question 8

Copper

Glass

Wood

Cloth

Solution

Question 9

$$\bigtriangleup Q = \bigtriangleup U + \bigtriangleup W$$

$$\bigtriangleup Q = \bigtriangleup U - \bigtriangleup W$$

$$\bigtriangleup Q = \bigtriangleup W - \bigtriangleup U$$

$$\bigtriangleup Q = -\bigtriangleup W - \bigtriangleup U$$

Solution

Question 10

$$\bigtriangleup U$$

$$\bigtriangleup U$$= negative

$$\bigtriangleup U$$ = positive

$$\bigtriangleup W$$ = zero

Solution

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Heat supplied goes into increasing internal energy and work done by gas.
Upon interpretation, we get the law of conservation of energy.
The first law of thermodynamics is based on the law of conservation of energy.