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Kinetic Theory Test - 12

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Kinetic Theory Test - 12
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  • Question 1
    1 / -0

    The difference between volume and pressure coefficients of an ideal gas is :

    Solution
    Volume coefficient: $$\alpha$$
    Pressure coefficient: $$\beta$$
    $$\alpha=\beta=\frac{1}{273}$$
  • Question 2
    1 / -0

    The P-T graph for the given mass of an ideal gas is shown in figure. Then the volume

    Solution
    From the graph it is clear that P is directly proportional to T. For an ideal gas it happens, when volume remains constant.
  • Question 3
    1 / -0

    A gas in an airtight container is heated from 25$$^{o}$$C to 90$$^{o}$$C. The density of gas will :

    Solution
    Since the container is airtight, volume will remain same, hence the density will remain same.
  • Question 4
    1 / -0

    The molar gas constant is the same for all gases because at the same temperature and pressure, equal volumes of gases have the same :

    Solution
    We know, $$R=\frac { PV }{ nT } $$
    assuming P,V and T to be constant.
    Also we know, that equal volume of gases contain equal number of molecules, hence the value of R is also constant.
  • Question 5
    1 / -0

    If the volume of the gas is to be increased by 4 times :

    Solution
    $$PV=RT$$
    At constant pressure temp has to be increased by 4 times to increase volume by 4 times.
  • Question 6
    1 / -0

    Three closed vessels A, B and C are at the same temperature T and contain gases which obey Maxwell distribution law of velocities. Vessel A contains $$O_2$$, B only $$N_2$$ and C mixture of equal quantities of $$O_2$$ and $$N_2$$. If the average speed of $$O_2$$ molecules in vessel A is $$V_1$$ and that of $$N_1$$ molecules in vessel B is $$V_2$$, then the average speed of the $$O_2$$ molecules in vessel C is

    Solution
    Vessel $$A:-O_2$$
    $$B:N_2$$
    $$C:O_2+N_2$$
    Average speed of one species do not depend on the others
    $$\therefore$$ avj. speed of $$V_2=V_1$$
  • Question 7
    1 / -0

    A gas at temperature 27$$^{0}$$C and pressure 30 atmospheres is allowed to expand to one atmospheric pressure. If the volume becomes 10 times its initial volumes, the final temperature becomes :

    Solution
    $$\dfrac { { P }_{ 1 }{ V }_{ 1 } }{ { T }_{ 1 } } =\dfrac { { P }_{ 2 }{ V }_{ 2 } }{ { T }_{ 2 } } \\ \dfrac { 30V }{ 300 } =\dfrac { 1\times 10V }{ { T }_{ 2 } } \\ { T }_{ 2 }=100K\\ { T }_{ 2 }=-173^0C$$
  • Question 8
    1 / -0

    The Universal gas constant may be expressed as :

    a) 8.31 J/mole-K         c) 2.00 J/mole-K

    b) 8.31 cal/mole-K       d) 2.00 cal/mole-K

    Solution
    In SI unit R= 8.31 J/mole-K
    In calorie units R = 2 cal/mole-K
  • Question 9
    1 / -0

    The parameter that determine the physical state of gas are :

    a) Pressure                  b) Volume

    c) Number of moles    d) Temperature

    Solution
    Surely gaseous state is determined only by pressure and volume of the substance at a particular temperature.
    There P,V and T are state parameters
  • Question 10
    1 / -0

    16 gm of $$O_{2}$$ gas and x gm of $$H_{2}$$ gas occupy the same volume at the same temperature and pressure. Then x is :

    Solution
    Equal volume of gas contains equal number of moles.
    16gm of oxygen = 0.5 mole.
    1mole of hydrogen =2gm.
    0.5mole of hydrogen = 1gm.
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