Kinetic Theory ...

During an experiment an ideal gas is found to obey an additional law V$$^{2}$$P= constant. The gas is initially at a temperature T and volume V. When it expands to a volume 2V, the temperature becomes

Two gases A and B having same pressure P, volume V and temperature T are mixed. if the mixture has volume and temperature as V and T respectively the pressure of mixture is

A vessel is filled with an ideal gas at a pressure of 200 atm and is at a temperature of 27$$^{0}$$ C. One half of the mass of the gas is removed from the vessel and the temperature of the remaining gas is increased to 87$$^{0}$$ C. At this temperature,the pressure of the gas will be

If $$\rho $$ is the density, m is the mass of 1 molecule and K is the Boltzman constant for a gas then the pressure of the gas is:

A gas is heated through $$1^{o}\ C$$ in a closed vessel. Its pressure is increased by $$0.4$$%. The initial emperature of the gas is

A given amount of a gas is heated till the volume and pressure both increase by $$2\%$$ each the percentage change in temperature of the gas is  equal to nearly

Two sample of Hydrogen and Oxygen of same mass possess same pressure and volume. The ratio of their temperature is

Two gases A&B having same pressure P, volume V and absolute temperature T are mixed. If the mixture has volume and temperature as V & T respectively then the pressure of mixture is

One litre of Helium gas at a pressure of 76 cm - Hg and temperature 27$$^{0}$$C is heated till its pressure and volume are doubled. The final temperature attained by the gas is

The mass of oxygen gas occupy a volume of 11.2 lit at a temperature 27$$^{0}$$C and a pressure of 76 cm of mercury in kilogram is (molecular weight of oxygen =32)