Kinetic Theory Test

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Kinetic Theory Test - 42

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Weekly Quiz Competition

Question 1
1 / -0

A quantity of air $$(\gamma = 1.4)$$ at 27$$^o$$C is compressed suddenly, the temperature of the air system will

A
fall

B
rise

C
remain unchanged

D
first rise and then fall

Solution

Since the gas is compressed suddenly, internal energy increases, so its temperature will increase as work is done on the gas.
Question 2
1 / -0

Which one of the following represents the correct arrangement in the increasing order of forces of attraction between their particles?

A
Water, air, oxygen

B
Air, sugar, oil

C
Oxygen, water, sugar

D
None of these

Solution

Gas molecules are at maximum distance from each other and have minimum force of attraction between them. Liquids have more force of attraction than gases while solids have maximum force of attraction.
So the given order is $$oxygen,water \ and \ sugar.$$
Question 3
1 / -0

Which of the following is the correct increasing order of the force of attraction between their particles?

A
Gold < water < Honey < Air

B
Air< Gold < Water < Honey

C
Air < Water < Honey < Gold

D
Water < Honey < Air < Gold

Solution

Air < Water < Honey < Gold

it is because the force of attraction increases in the order Gas < Liquid < Solid
and Air is gas

Water is liquid and Honey is a viscous liquid and Gold is solid

Hence, te correct option is $$\text{C}$$
Question 4
1 / -0

For a given gas, which of the following relationships is correct at a given temp?

A
$$u_{rms} > u_{av} > u_{mp}$$

B
$$u_{rms} < u_{av} < u_{mp}$$

C
$$u_{rms} > u_{av} < u_{mp}$$

D
$$u_{rms} < u_{av} > u_{mp}$$

Solution

$$u_{rms} = $$ Root mean square velocity
$$u_{ar}= $$Average velocity
$$u_{mp} $$= Most probable velocity
$$u_{mp}:u_{ar}:u_{rms}= 1: 1.128: 1224$$
$$\therefore u_{rms} > u_{ar} > u_{mp}$$
Question 5
1 / -0

Kinetic energy of the particles:

A
is the energy of the bulk matter

B
decreases with increase in temperature

C
increases with increase in temperature

D
temperature has no effect on kinetic energy

Solution

The average molecular kinetic energy is proportional to the ideal gas law's absolute temperature which explains that with increase in temperature of the system the kinetic energy of the molecules increases as they are directly proportional to each other.
Question 6
1 / -0

The quantity of heat required to heat 1 mole of a monoatomic gas through one degree K at constant pressure is:

A
3.5 R

B
2.5 R

C
1.5 R

D
none of these

Solution

Quantity of hear required $$= n.C_p. \Delta T$$
Here, $$n= 1, \Delta T = K $$
For monoatomic gases, $$C_p=C_V+R$$
$$=1.5 R+R =2.5R$$.
$$\therefore $$ Heat required $$= C_p= 2.5 R$$
Question 7
1 / -0

The volume of mole of a prefect gas at NTP is ______.

A
22.4 litres

B
2.24 litres

C
100 litres

D
none of these

Solution

At NTP is normal temperature and pressure.
$$\Rightarrow$$ Pressure $$=1\;atm\;;T=293k\;;R=0.08205\dfrac{L\;atm}{mol}$$
$$\Rightarrow V=\dfrac{RT}{P}$$
$$\Rightarrow V=\dfrac{(0.08205)293}{1\;atm}$$
$$\Rightarrow V_{molar}=22.4\;L$$
Hence, the answer is $$22.4\;L.$$
Question 8
1 / -0

The volume of a perfect gas at NTP is

A
22.4 litres

B
2.24 litres

C
100 litres

D
None of these

Solution

At NTP
Pressure $$=1$$ atm
Temperature $$=293k$$
According to ideal gas equation $$PU=nRT$$
$$\Rightarrow V=\dfrac{1\;mol\;(0.08205)293}{1\;atm}$$
$$\Rightarrow (For\;n=1)\;V=22.4\;L$$
Hence, the answer is $$22.4\;L.$$
Question 9
1 / -0

When we cool a gas below its condensation point, the KE of its molecules will

A
increase

B
decrease

C
remains the same

D
first increase then decrease

Solution

When we cool a gas below its condensation point, the kinetic energy of gas decreases and particles come closer and their inter molecules forces increases and they bond with each other and converts to liquid.
Hence, the answer is decrease.
Question 10
1 / -0

When an inflated tyre bursts, the air escaping out __________.

A
will get heated up

B
will be cooled

C
will not undergo any change in its temperature

D
will be liquefied

Solution

Bursting of a tyre is an adiabatic expansive i.e, $$dQ=0$$ $$\&$$ $$dV=+ve$$
So, According to first law of thermodynamic $$dQ=dV+PdV$$
$$\Rightarrow -PdV=dV=CvdT$$
As $$P$$ is $$+ve$$ $$dV$$ is $$+V$$ thus $$dV=-ve$$
So, $$dT$$ is $$-ve$$ means decrease in temperature.
Hence, the answer is will be cooled.

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Kinetic Theory Test - 42

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Kinetic Theory Test - 42

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SHARING IS CARING

Question 1

fall

rise

remain unchanged

first rise and then fall

Solution

Question 2

Water, air, oxygen

Air, sugar, oil

Oxygen, water, sugar

None of these

Solution

Question 3

Gold < water < Honey < Air

Air< Gold < Water < Honey

Air < Water < Honey < Gold

Water < Honey < Air < Gold

Solution

Question 4

$$u_{rms} > u_{av} > u_{mp}$$

$$u_{rms} < u_{av} < u_{mp}$$

$$u_{rms} > u_{av} < u_{mp}$$

$$u_{rms} < u_{av} > u_{mp}$$

Solution

Question 5

is the energy of the bulk matter

decreases with increase in temperature

increases with increase in temperature

temperature has no effect on kinetic energy

Solution

Question 6

3.5 R

2.5 R

1.5 R

none of these

Solution

Question 7

22.4 litres

2.24 litres

100 litres

none of these

Solution

Question 8

22.4 litres

2.24 litres

100 litres

None of these

Solution

Question 9

increase

decrease

remains the same

first increase then decrease

Solution

Question 10

will get heated up

will be cooled

will not undergo any change in its temperature

will be liquefied

Solution

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