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Kinetic Theory Test - 71

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Kinetic Theory Test - 71
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  • Question 1
    1 / -0
    If Cv = 4.96 cal / mole K, then increase in internal energy when temperature of 2 moles of this gas is increased from 340 K to 342 K
    Solution
    Change in internal energy is always equal to the heat supplied at constant volume. $$ \Delta U = \left ( \Delta Q \right )_{v}= \mu C_{v}\Delta T.$$
    So, $$\Delta U=2\times 4.96\times (342-340)=19.84 cal$$
  • Question 2
    1 / -0
    The degrees of freedom of a triatomic gas is 
    Solution
    The general expression for degree of freedom is $$DOF=3N−n$$
    here, DOF means degree of freedom, N is number of particle, and n is the number of holonomic constraints.
    for a triatomic molecule, the number of particle is 3 and since the separation between three atoms are fixed so, the number of constraints is 3.
    hence, $$DOF=(3\times 3)−3$$
    $$DOF=9−3$$
    $$DOF=6$$

  • Question 3
    1 / -0
    A monoatomic gas molecules has 
    Solution

  • Question 4
    1 / -0
    At a given volume and temperature , the pressure of a gas
    Solution

  • Question 5
    1 / -0
    A diatomic molecules has how many degrees of freedom 
    Solution

  • Question 6
    1 / -0
    In an ideal gas, the molecules possess
    Solution
    In an ideal gas, the molecules only have $$\textbf{ kinetic energy}$$
  • Question 7
    1 / -0
    The degrees of freedom of a stationary rigid body about its axis will be 
    Solution

  • Question 8
    1 / -0
    The pressure exerted by the gas on the walls of the container because
    Solution

  • Question 9
    1 / -0
    The mean kinetic energy of a gas at $$300\,K $$ is $$100J$$. The mean energy of the gas at $$450\,K $$ is equal to 
    Solution

  • Question 10
    1 / -0
    Mean kinetic energy per degree of freedom of gas molecules is 
    Solution

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