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Kinetic Theory Test - 8

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Kinetic Theory Test - 8
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  • Question 1
    1 / -0

    Calculate the change in internal energy of 3.00 mol of helium gas when its temperature is increased by 2.00 K.

    Solution

    Helium is a monoatomic gas.(C= 1.5R)

    change in internal  energy 

    ΔU = nCV Δ T = 3 × 1.5 × 8.31 × 2 = 75J

  • Question 2
    1 / -0

    One mole of hydrogen gas is heated at constant pressure from 300 K to 420 K. Calculate the energy transferred by heat to the gas

    Solution

    Hydrogen is a diatomic gas. (C= 3.5R)

    energy transferred by heat to the gas

    Q = nCP Δ T = 1 × 3.5 × 8.31 × 120 = 3490J

  • Question 3
    1 / -0

    One mole of hydrogen gas is heated at constant pressure from 300 K to 420 K. Calculate the increase in its internal energy.

    Solution

    Hydrogen is a diatomic gas. (C= 2.5R)

    Change in internal energy 

    ΔU = nCVΔT = 1 × 2.5 × 8.31 × 120 = 2493J

  • Question 4
    1 / -0

    One mole of hydrogen gas is heated at constant pressure from 300 K to 420 K. Calculate the work done by the gas.

    Solution

    In  isobaric process 

    W = nR(TF − TI) = 1 × 8.31 × (420 − 300) = 0.98kJ

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