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Kinetic Theory Test - 86

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Kinetic Theory Test - 86
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  • Question 1
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    When 1 mole of a monoatomic gas expands at constant pressure the ratio of the heat supplied that increases the internal energy of the gas and that used in expansion is
    Solution

  • Question 2
    1 / -0
    One mole of a perfect gas in a cylinder fitted with a piston has a pressure P, volume V and temperature is increased by 1 K keeping pressure constant , the increase in volume is
    Solution

  • Question 3
    1 / -0
    If distance between the gas molecules is doubled on constant temperature , then pressure . 
    Solution

  • Question 4
    1 / -0
    A vessel of volume $$  V=5.0  $$ liters contains 1.4 $$ \mathrm{g}  $$ of nitrogen at temperature $$  T=1800 \mathrm{K}  $$ . Find the pressure of the gas if 30$$  \%  $$ of its molecules are dissociated into atoms at this temperature.
    Solution

  • Question 5
    1 / -0
    A vessel of volume $$5000 { cm }^{ 3 }$$ contains (1/20) mole of molecular nitrogen at 1800 K. If 30% of the molecules are now dissociated the pressure inside the vessel in Pa will be-
    Solution

  • Question 6
    1 / -0
    The mean kinetic energy of one mole of gas per degree of freedom (on the basis of kinetic theory of gases) is:
    Solution

  • Question 7
    1 / -0
    A balloon weighting 50kg is filled with 685.2kg of helium at 1 atm pressure and at $${ 25 }^{ o }$$C. What will be its displaced 51087 kg of air ?
  • Question 8
    1 / -0
    Two containers  $$A$$  and  $$B$$  contain molecular gas at same temperature with masses of molecules are  $${ m }_{ { { A } } }$$  and  $${ m }_{ { { B } } }$$   then relation of momentum  $${ P }_{ { A } }$$  and  $${ P }_{ { { B } } }$$  will be
    Solution

  • Question 9
    1 / -0
    The mass of glucose that should be dissolved in 100 g of water in order to produce same lowering of vapour pressure as is produced by dissolving 1 g of urea (mol. Mass = 60) in 50 g of water is : (Assume dilute solution in both cases) 
    Solution

  • Question 10
    1 / -0
    At what temperature does the average translational kinetic energy of a molecule in a gas become equal to kinetic energy of an electron accelerated from rest through a potential difference of $$1$$ volt? ($$k=1.38\times{!0}^{-23}J/k$$)
    Solution

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