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Waves Test - 25

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Waves Test - 25
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Two small boats are $$10m$$ apart on a lake. Each pops up and down with a period of  $$4.0\ \text{seconds}$$ due to wave motion on the surface of the water. When one boat is at its highest point, the other boat is at its lowest point. Both boats are always within a single cycle of the waves. The speed of the waves is
    Solution
    $$\dfrac{\lambda}{2}=10\ \text{m}\Rightarrow \lambda=20\ \text{m}$$

    $$\text{Time period}= T=4\ \text{sec}$$

    $$ V=\dfrac{\lambda}{T}=\dfrac{20}{4}=5\ \text{m/s}$$
  • Question 2
    1 / -0
    If the frequency of a wave is increased by 25 %, then the change in its wavelength will be:
    (medium not changed)
    Solution
    Since, the medium has not changed, speed of wave remains
    same.
    $$v=\nu_1 \lambda_1=\nu_2 \lambda_2$$
    $$\nu_2=1.25 \nu_1$$
    $$\lambda_2=\dfrac{\nu_1}{\nu_2} \lambda_1=\dfrac{1}{1.25} \lambda_1=(4/5) \lambda_1$$
    $$ \dfrac {\Delta \lambda}{\lambda _1} = \dfrac{\lambda_2- \lambda_1}{\lambda_1} \times 100= \dfrac{(4/5)\lambda_1- \lambda_1}{\lambda_1} \times 100=-(1/5)\times 100=-20$$ %
    option "B" is correct.
  • Question 3
    1 / -0
    An object is vibrating at $$50$$ hertz. What is its time period?
    Solution
    From the definition of frequency $$\nu= \dfrac{1}{T}$$ 

    and we are given $$\nu=50 hertz $$.

    Substituting, we have $$50 = \dfrac{1}{T}$$ or

    $$T = 0.02 s$$

  • Question 4
    1 / -0
    The frequency of a man's voice is 300 Hz and its wavelength is 1 meter. If the wavelength of a child's voice is 1.5 m, then the frequency of the child's voice is :
    Solution
    $$\nu_1\lambda_1= \nu_1\lambda_1$$ since $$v= \nu\lambda$$ is same for both a man and child.

    $$ \therefore 300 \times 1 =  \nu_2 \times  1.5$$

    $$ \Rightarrow \nu_2 = 200 \: Hz$$
  • Question 5
    1 / -0
    Sound waves are .................... waves.
    Solution
    Sound waves are called longitudinal waves because sound requires a material medium for their propagation.
    Hence, the correct option is B
  • Question 6
    1 / -0
    Frequency of the sinusoidal wave, y = 0.40 cos (2000t + 0.080) would be :
    Solution
    The general form of a sinusoidal wave is,
    $$y=A cos(2\pi\nu t+\phi)$$, where,
    $$A=$$amplitude of the wave
    $$\nu= $$frequency
    $$\phi=$$phase shift
    Comparing this with the given equation then the frequency will comes out to be,
    $$\omega = 2\pi f $$
    Here $$\omega = 2000$$ Therefore will get frequency as,
    $$\omega = 2\pi f = 2000$$
    Calculating,
    $$f=318\  Hz$$
  • Question 7
    1 / -0
    The frequency of sound waves is 11 kHz and its wavelength is 20 cm, then the velocity of sound waves is :
    Solution
    Velocity of sound wave  $$V=n \lambda$$ i.e. the product of the frequency and amplitude of the wave. 

    So, $$V=11 \times 10^3 \times 20 \times 10^{-2}=2200$$ m/s
  • Question 8
    1 / -0
    The type of waves is/ are
    Solution

  • Question 9
    1 / -0
    If the vibration of particles in a wave is perpendicular to the direction of propagation of wave, then it is called,
    Solution

  • Question 10
    1 / -0
    Elastic waves in solid are :
    Solution
    Elastic wave, motion in a medium in which, when particles are displaced, a force proportional to the displacement acts on the particles to restore them to their original position. so depending on the forces acting the waves may be either longitudinal or transverse .
    the answer is C.
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