Waves Test - 60...

Two waves of equal amplitude when superposed , give a resultant wave having an amplitude equal to that of either wave. The phase difference between the two waves is

The phase difference between two points separated by 0.8 m in a wave of frequency 120 Hz is 0.5 $$\pi $$ the wave velocity is

Two SHM are represented by equations
$${ y }_{ 1 }=6cos\left( 6\pi t+\dfrac { \pi  }{ 6 }  \right) ,{ y }_{ 2 }=3\left( \sqrt { 3 } sin3\pi t+cos3\pi t \right) $$

Two particles undergo SHM along same line with   same time period (T) and same amplitude  (A) At particular instant one particle is x = - A and the other is at x = 0 If they move in same direction then they will meet each other at

Two particles execute S.H.M. of same amplitude and frequency along the same straight line. They pass one another, when going in opposite directions, each time their displacement is half of their amplitude. The phase-difference between them is

When a wave travels in a medium, the particle displacement is given by y(xt)=0.03 sin $$\pi $$ (2t-0.01 x) where y and x are meters and t in seconds. The phase difference, at a given instant of time between two particle 25 m. apart in the medium, is 

The phase difference between two waves represented by 
$${ y }_{ 1 }={ 10 }^{ -6 }sin\left[ 100t+\left( \times /50 \right)  \right] m$$
$${ y }_{ 2 }={ 10 }^{ -6 }cos\left[ 100t+\left( \times /50 \right)  \right] m$$
where x is expressed in meters and t is expressed in seconds, is approximately

the amplitude and frequency of a wave represented by the equation $$ Y= 2 A cos^2 (kx-wt) $$ are :

The equation of $$SHM$$ with amplitude $$4m$$ and time period $$2sec$$ with initial phase $$\dfrac{\pi}{3}$$ is $$y =$$

The figure shown an instantaneous profile of a rope carrying a progressive mave moving from left to right, then :-
(A)  The phase at A is greater then the phase at B 
(B)  The phase at B is greater then the phase at A
(C)  A is moving upwards
(D) B is moving upwards