Waves Test - 62...

For a wave displacement amplitude is $$10^-4 m$$,density of air 1.3 kg $$m^-4$$,velocity in air 340 $$ms^-4$$ are frequency is 2000 Hz.The intensity of wave is

The S.H.M. of a particle is given by the equation $$y = 3 \sin \omega t + 4 \cos \omega t .$$The amplitude is

Two equations of two SHM are
$$x=a \ sin(\omega t - \alpha) \ and \ y=b \ cos(\omega t - \alpha)$$
The phase difference between the two is 

Three simple harmonic motions in the same direction having the same amplitude $$a$$ and period are superposed. IF each differs in phase from the next by $${45}^{o}$$ then

Four waves of the equation given by 
$$y_1= 5A \ sin \ (wt - Kx + \pi/2)$$
$$y_2= 2A \ sin \ (wt - Kx + 3 \pi/2)$$
$$y_3= 6A \ sin \ (wt - Kx)$$
and   $$y_4= 2A \ sin \ (wt - Kx + \pi)$$

A particle moving along a straight line with a constant acceleration of - 4 m per second square passes through a point on the line with a velocity of + 8 metre per second at the moment when the distance travelled by the particle in 6 second in 5 seconds

Equations of motion in the same direction are given by:
$$y_1 = a \ sin \ (\omega t - kx)$$
$$y_2 = a \ sin \ (\omega t - kx - \theta)$$
The amplitude of the medium particle will be:

Equations of motion in the same direction are given by:
$$y_1 = 2a \ sin \ (\omega t - kx)$$
$$y_2 = 2a \ sin \ (\omega t - kx - \theta)$$
The amplitude of the medium particle will be:

A small mass executes linear SHM about $$O$$ with amplitude $$a$$ and period $$T$$. Its displacement from $$O$$ at time $$T/S$$ after passing through $$O$$ is

If the fundamental frequency of string is $$220 \mathrm { cps }$$, the frequency of fifth harmonic will be