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Waves Test - 81

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Waves Test - 81
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Weekly Quiz Competition
  • Question 1
    1 / -0
    A wave of frequency 400 Hz has a velocity of 320 $$ms^{-1}$$. The distance between the particles differing in phase by $$90^o$$ is
    Solution

  • Question 2
    1 / -0
    Which of the following equations does not represent a progressive wave ?
  • Question 3
    1 / -0
    The spherical waves are emitted in a medium by a source of 5 watt. Assuming that medium does not absorbed energy,the intensity of wave at a distance of 5m from source will be
    Solution

  • Question 4
    1 / -0
    Sinusoidal wave having frequency $$500Hz$$ and speed $$800m/s$$.If two point in the medium are separated by distance z having phase difference $$\frac{\pi }{6},$$ then x is 
    Solution

  • Question 5
    1 / -0
    Consider a wave with frequency  $$300\mathrm { Hz }$$  and speed  $$350\mathrm { ms } ^ { - 1 } .$$  How far apart are two points  $$60 ^ { \circ }$$  out of phase?
    Solution

  • Question 6
    1 / -0
    The energy in the superposition of waves:
  • Question 7
    1 / -0
    The displacement $$y$$ of a particle, if given by $$y=4\cos^2\left(\dfrac{t}{2}\right)\sin(1000t)$$. This expression may be considered to be a result of the superposition of how many simple harmonic motions?
    Solution
    $$\because$$ Equation of displacement of particle is
    $$y=4\cos^2(\dfrac{t}{2})\sin (1000t)$$...........(i)

    Or $$y=4[\left(\dfrac{1+\cos t}{2}\right)\sin1000t]$$

    $$(\because \cos^2x=\dfrac{1+\cos 2x}{2})$$

    Or $$y=3\sin 1000t+2\cos t\sin 1000 t$$
    Or $$y=2\sin 1000t+\sin 1001t+\sin t 999t$$
    $$[2\sin A\cos B=\sin (A+B)+\sin (A-B)]$$
    Hence, equation $$(i)$$ is the result of the superposition of three simple harmonic motion.
    So, the correct option will be $$(B)$$
  • Question 8
    1 / -0
    Source $$S$$ emits microwaves with a constant amplitude. The microwave hit a metal screen $$P$$ and are reflected. A stationary wave is formed between $$S$$ and $$P$$. The wavelength of the microwaves is much smaller than the distance between $$S$$ and$$P$$
    A detector $$Q$$ is moved at a slow, constant speed from $$S$$ to $$P$$
    What happens to the amplitude of the signal detected by $$Q$$>

    Solution
    Since the stationary wave is formed ,so there will be Nodes and Antinodes.
    We are told that the wavelength of microwave is much smaller than the distance between the S and P.
    This means that the stationary wave consists of several wavelength and thus many Nodes (N) and Antinodes (A) are present.
    That is like 
    $$N\ A\ N\ A\ N\ A\ N\ .......$$
    The amplitude of the signal detected by Q would increases (at Antinodes) and decreases (at Nodes).

  • Question 9
    1 / -0
    A traveling wave is represented by the equation $$ y = \frac{1}{10} sin(60 t + 2x) $$, where x and y in meters and t is in second . this represents a wave
    (1) of frequency $$ \frac {30}{\pi} Hz $$
    (2) of wavelength $$ \pi m $$
    (3)of amplitude 10 cm
    (4) moving in the positive x direction
    pick out the correct statements from the above.
  • Question 10
    1 / -0
    String $$I$$ and $$II$$ identical lengths and linear mass densities but string $$I$$ is under greater tension than string $$II$$. The accompanying figure shows four different situation, $$A$$ to $$D$$ in which standing wave patterns exists on the two strings. In which situation is it possible that strings $$I$$ and $$II$$ are oscillating at the same resonant frequency?
    Solution
    As we know,
    $$v\propto \sqrt T$$

    and since $$T_1>T_2$$

    then $$v_1>v_2$$

    and for both string to have same frequency

    $$\lambda _1>\lambda _2$$

    this is only shown in option C
    so, option (C) is correct.
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