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Units and Measurements Test - 23

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Units and Measurements Test - 23
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  • Question 1
    1 / -0
    The dimensional formula $${ M }^{ -1 }{ L }^{ 3 }{ T }^{ -2 }$$ refers to :
    Solution
    Force $$=MLT^{-2}$$
    Power $$=ML^{2}T^{-3}$$
    Energy $$=ML^{2}T^{-2}$$
    Gravitation constant 
    $$=M^{-1}L^{3}T^{-2}$$
  • Question 2
    1 / -0
    The dimensional formula for angular velocity is:
    Solution

    $$Angular \ velocity,

    W=\dfrac{1}{Time}=T^{-1}M^{0}L^{0}$$

  • Question 3
    1 / -0
    The dimensions of calorie are :
    Solution
    Its a unit of energy whose dimensions can be calculated as $$F.dr=MLT^{-2}L=ML^2T^{-2}$$
  • Question 4
    1 / -0
    The dimensions of resistivity in terms of M, L, T and Q, where Q stands for the dimensions of charge is :
    Solution
    $$R=\dfrac{\rho l}{A}$$
    Power $$=I^2R$$
    Dimension of R is $$\dfrac{ML^2{T}^{-1}}{Q^2T^{-2}}=ML^2TQ^{-2}$$
    Now by equation, $$\rho=\dfrac{RA}{L}=ML^2TQ^{-2}L=ML^3TQ^{-2}$$
    Hence, option A is correct.
  • Question 5
    1 / -0
    Which of the following pair does not have the same dimensions?
    Solution
    Moment of inertia $$={mr}^{2}={ML}^{2}$$
    Torque $$=M^{1}L^{2}T^{-2}$$
    Linear momentum $$=mv=MLT^{-1}$$
    Impulse $$=MLT^{-1}$$
    Angular momentum 
    $$=ML^{2}T^{-1}$$
    Planks constant$$=ML^{2}T^{-2}$$
    Work $$=ML^{2}T^{-2}$$
    Internal Energy 
    $$=ML^{2}T^{-2}$$
    Hence, option A is correct.
  • Question 6
    1 / -0
    The dimensional formula for impulse is:
    Solution

    $$Impulse=force\times
    time=ML^{1}T^{-2}\times T^{1}$$$$=MLT^{-1}$$

  • Question 7
    1 / -0
    The SI unit of a physical quantity having the dimensional formula of $${ ML }^{ 0 }{ T }^{ -2 }{ A }^{ -1 }$$ is:
    Solution
    $$amp$$ $$m^{2}=A^{1}L^{2}$$
    $$amp$$ $$meter$$$$=A^{1}L^{1}$$
    $$weber$$ $$=ML^{2}A^{-1}T^{-2}$$
    $$A\rightarrow $$ ampere
    $$Tesla$$ 
    $$=M^{1}L^{0}T^{-2}A^{-1}$$
    Hence, option A is correct answer.
  • Question 8
    1 / -0
    According to theory of significant figures the value of $$\sqrt { 3.0 } $$ is:
    Solution
    $$\sqrt{3.0}=1.732$$
    Since 3.0 has 2 significant figure,
    So, our answer should have 2 significant figure
    i.e. $$1.732\approx 1.7$$
  • Question 9
    1 / -0
    The number of significant figures in the numbers $$672.9$$ and $$2.520\times { 10 }^{ 7 }$$ are :
    Solution

    $$672.9 \rightarrow 6, 7, 2, 9 \rightarrow$$ 4 significant digits since all non zero digits are significant.
    $$2.520\times 10^{7} \rightarrow 2, 5, 2, 0 \rightarrow 4$$ significant digits, since all the zero on the right side of last non zero digit in the decimal part are significant.

  • Question 10
    1 / -0
    The dimensional formula for Areal velocity is :
    Solution
    It is the area covered per unit time $$\dfrac{dA}{dt}=L^2T^{-1}$$
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