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Units and Measurements Test - 30

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Units and Measurements Test - 30
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  • Question 1
    1 / -0
    The dimensions of magnetic moment are
    Solution
    Magnetic moment is given as $$M=current\times area-AL^2=[L^2A^1]$$
  • Question 2
    1 / -0
    The unit and dimensions of impedance in terms of charge Q are
    Solution
    Unit of impedance is $$ohm $$ and
    Dimension of Impedance $$=\dfrac {V}{I}=\dfrac {W}{QI}=\dfrac {ML^2T^{-2}}{QQT^{-1}}$$$$=[ML^2T^{-1}Q^{-2}]$$
  • Question 3
    1 / -0
    If $$L$$ and $$R$$ denote inductance and resistance then dimension of $$L/R$$ is
    Solution
    The ratio $$\dfrac {L}{R}=\dfrac {[ML^2T^{-2}A^{-2}]}{[ML^2T^{-3}A^{-2}]}=T=[M^0L^0T^1]$$
  • Question 4
    1 / -0
    The dimensional formula of current density is
    Solution
    Current density $$=\dfrac {Current}{area}=\dfrac {Q}{area\times t}=[M^0L^{-2}T^{-1}Q]$$
  • Question 5
    1 / -0
    The dimensional formula for relative refractive index is
    Solution
    Relative refractive index $$ { \mu  }_{ r }$$is a ratio of refractive index of medium $$ \mu $$ to refractive index of vacuum $$ { \mu  }_{ o }$$.
    Hence dimensionless $$\mu_r=\dfrac {\mu}{\mu_0}=[M^0L^0T^0]$$
  • Question 6
    1 / -0
    Which physical quantities have same dimensions?
    Solution
    Moment of couple $$=$$ force $$\times$$ perpendicular distance $$=[M^1L^2T^{-2}]$$
    Work $$= $$ force $$\times$$ distance $$=[M^1L^2T^{-2}]$$
    They have the same dimension.
  • Question 7
    1 / -0
    The dimensions of Wien's constant are
    Solution
    Here $${ \lambda  }_{ m }$$ is maximum wavelength at temperature $$T$$
    Wien's constant  $$b$$ is given as  $$b=\lambda_mT=LK=[M^0L^1T^0K^1]$$
  • Question 8
    1 / -0
    The dimensional formula of couple is
    Solution
    Dimensionally couple $$=Torque = Force\times distance=[MLT^{-2}][L]=[ML^{2}T^{-2}]$$
  • Question 9
    1 / -0
    The dimensional formula of arial velocity is
    Solution
    In classical mechanics, areal velocity is the rate at which area is swept out by a particle as it moves along a curve.
    Areal velocity $$=\frac {area}{time}$$$$=[M^0L^{2}T^{-1}]$$
  • Question 10
    1 / -0
    If $$I$$ is the moment of inertia and $$\omega$$ the angular velocity, what is the dimensional formula of rotational kinetic energy, $$\dfrac {1}{2}I\omega^2$$?
    Solution
    Dimensionally rotational kinetic energy $$=Work$$ $$done=Energy$$ $$=[ML^{2}T^{-2}]$$
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