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Units and Measurements Test - 32

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Units and Measurements Test - 32
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  • Question 1
    1 / -0
    The dimensions of magnetic field in $$M, L, T$$ and $$C$$ (coulomb) are given as
    Solution
    Force $$F$$ acting on charge $$q$$ moving with velocity $$v$$ in magnetic field $$B$$ is given as $$F=qvB$$ thus $$B=\dfrac {F}{qv}$$
    $$\therefore [B]=\dfrac {[F]}{[qv]}=\dfrac {MLT^{-2}}{C\times LT^{-1}}=[MT^{-1}C^{-1}]$$
  • Question 2
    1 / -0
    1 $$\mathring{A}$$ is equal to :
    Solution
    1 Angstorm = $$1 \times 10^{-10} $$ m = $$0.1 \ nm$$  ($$10^{-9}$$ m)
  • Question 3
    1 / -0
    Which of the following quantities has a unit but dimensionless?
    Solution
    Angular displacement has unit (degree or radian) but it is dimensionless as it is the ratio of like quantities
  • Question 4
    1 / -0
    Using mass $$(M)$$, length $$(L)$$, time $$(T)$$ and current $$(A)$$ as fundamental quantities, the dimension of permeability is
    Solution
    Magnetic permeability is a constant of proportionality that exists between magnetic induction and magnetic field intensity. 

    In SI units, permeability is measured in henries per meter $$H/m$$ or $$H m^{-1}$$.
    Henry has the dimensions of $$[ML^2T^{-2}A^{-2}]$$.
    Dimensions for magnetic permeability will be $$[ML^2T^{-2}A^{-2}]/[L]=$$$$[MLT^{-2}A^{-2}]$$
  • Question 5
    1 / -0
    Count total number of Significant Figures in 3.0800
    Solution
    S.F. = Five, as trailing zeros after decimal place are significant.
  • Question 6
    1 / -0
    Count total number of significant figures in 3500
    Solution
    S.F. = Two , the trailing zeros are not significant.
  • Question 7
    1 / -0
    Dimensional formula of power is :
    (West Bengal/NTSE Stage-l/2013)
    Solution
    power$$=\cfrac{work}{time} ; work=force\times displacement ; $$
    $$Force=mass\times acceleration $$;
    $$acceleration=\cfrac{velocity}{time}$$ ;
    $$velocity=\cfrac{displacement}{time}$$
    $$acceleration=\cfrac{velocity}{time}=\cfrac{\left[ L \right]}{\left[ T^2 \right] }$$
    $$P=\cfrac{Work}{Time}=\cfrac{Force \times displacement}{Time} =\cfrac{\left[ M \right] \times \cfrac{\left[ L \right]}{\left[ T^2 \right] } \times L}{T}=\cfrac{\left[ MLL \right] }{T^3}=\left[ ML^2T^{-3} \right] $$
    Hence, option $$B$$ is correct.
  • Question 8
    1 / -0
    A physical quantity $$X$$ is expressed as velocity $$\displaystyle =\sqrt{\dfrac{X}{Density}}$$ The dimension of $$X$$ are 
    Solution

    $$[X]=[(velocity)^{2}Density]$$

           $$=[(L^{2}T^{-2})ML^{-3}]=[ML^{-1}T^{-2}]$$

  • Question 9
    1 / -0
    Count total number of significant figures in 0.00418
    Solution
    S.F. = Three, as leading  zeros are not significant.
  • Question 10
    1 / -0
    The magnetic moment has dimensions of
    Solution

    Magnetic moment of a coil carrying current is,

    $$M = I.A$$

    [A is area of cross section and i is current]

    Dimension of $$M = AL^{2}$$

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