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Motion in A Straight Line Test - 14

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Motion in A Straight Line Test - 14
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  • Question 1
    1 / -0
    Unit of acceleration is
    Solution
    acceleration  $$ = \dfrac{dv}{dt}$$
    Units of 'v' is m/s and 't' is seconds
    Therefore units of acceleration is $$\dfrac{m}{s^2} $$
  • Question 2
    1 / -0
    A body initially moving with a velocity of $$5\ ms^{-1}$$ attains a velocity of $$25\ ms^{-1}$$ in $$5\ s$$, find the acceleration of body in $$ms^{-2}.$$
    Solution
    Acceleration $$ = \dfrac{\text{Final velocity - initial velocity}}{\text{time taken}}$$

    Final velocity $$v = 25 m/s $$
    Initial velocity $$u = 5 m/s $$
    a $$= \dfrac{25 - 5}{5} m/s^2$$
    a $$= 4 m/s^2 $$
  • Question 3
    1 / -0
    If the velocity of a body does not change, its acceleration is
    Solution
    Acceleration of a body is defined as the rate of change of the velocity of the body. Now since the velocity doesn't change at all, the rate of change will be zero.
    So, acceleration = 0
  • Question 4
    1 / -0
    The velocity of an object increases at a constant rate from $$20 m s^{-1}$$ to $$50 m s^{-1}$$in 10 s. Find the acceleration.
    Solution
    Acceleration $$a=\dfrac {v-u}{t}=\dfrac{50  \ m s^{-1}-20  \ m s^{-1}}{10 s}$$
    or $$ a=\dfrac{30  \ m s^{-1}}{10 s}$$
    $$= 3 \ m s^{-2}$$
  • Question 5
    1 / -0
    The velocity of a body can change
    Solution
    Acceleration is defined as change of velocity in unit time. So if acceleration is zero, there is no change of velocity, the body is moving with a constant velocity.
  • Question 6
    1 / -0
    A bomb is released from a horizontal flying aeroplane .The trajectory of bomb as observed from ground is
    Solution
    When thrown from aeroplane , it will have velocity in horizontal direction. Thus angle between velocity and acceleration (i.e. gravity) is neither 0 nor 180 so, it wil be pprojectile motion (i.e. parabola in shape).
  • Question 7
    1 / -0
    Unit for the rate of change of velocity is
    Solution
    Velocity units $$ = m/s$$
    Acceleration is the rate of change of velocity
    a $$= \dfrac{change \ in \ velocity }{time } $$
    Therefore SI units of acceleration is $$ms^{-1}/s = \dfrac{m}{s^2} $$
  • Question 8
    1 / -0
    A block is released from rest at the top of a friction-less inclined plane 16 m long. It reaches the bottom 4 sec later. A second block is projected up the plane from the bottom. At the instant at which the block is released in such a way that it returns to the bottom simultaneously with the first block. The acceleration of each block on the incline is :
    Solution
    Acceleration of both the blocks will be the same on the inclined plane
    Let it be '$$a$$'
    So, according the the equation of motion
    $$\frac { 1 }{ 2 } \times a\times { 4 }^{ 2 }=16\Rightarrow a=2m/{ s }^{ 2 }$$
  • Question 9
    1 / -0
    Which of the following is/are true about acceleration
    Solution
    Acceleration =$$\dfrac{Final\ velocity\ - Initial\ velocity }{time}$$ 

    Its SI unit is =$$ms^{-1}/s=m/s^2$$

    A negative acceleration acts opposite to the direction of motion of object and it reduces the velocity , it called retardation. 
  • Question 10
    1 / -0
    An object is thrown vertically upwards and rises to a height of 10 m. Calculate the velocity with which the object was thrown upwards :
    Solution
    $$v^2=u^2+2as$$
    $$0=u^2+2(-9.8)(10)$$
    $$u= \sqrt{2\times9.8\times10}= 14 m/s$$
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