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Motion in A Plane Test - 5

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Motion in A Plane Test - 5
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  • Question 1
    1 / -0

    if particles A and B are moving with velocities vA and vB (each with respect to some common frame of reference, say ground.). Then, velocity of particle A relative to that of B is:

    Solution

    The relative velocity of an object A with respect to another object B is the velocity that object A would appear to have to an observer situated on object B moving along with it.

    In simple words relative velocity of A with respect to Be is the vector difference between the velocities of A and B.

    It is represented as 

    VAB = VA− VB

  • Question 2
    1 / -0

    The path of a projectile is 

    Solution

    A particle with a vertical and horizontal velocity travelling in a gravitational field will trace out a parabola.

  • Question 3
    1 / -0

    Centripetal acceleration of a particle moving in a circular path with constant velocity v is given by

    Solution

    A body that moves in a circular motion (of radius R) at constant speed (v) is always being accelerated. The acceleration is at right angles to the direction of motion (towards the center of the circle) and of magnitude  v2/R

  • Question 4
    1 / -0

    The component of a vector r along X-axis will have maximum value if

    Solution

    r is along positive X-axis

  • Question 5
    1 / -0

    Which of the following algebraic operations on vectors not permissible?

    Solution

    Although vectors and scalars represent different types of physical quantities, it is sometimes necessary for them to interact. While adding a scalar to a vector is impossible because of their different dimensions in space, it is possible to multiply a vector by a scalar.

  • Question 6
    1 / -0

    Which of the following statements false?

    Solution

    A displacement is vector that is the shortest path length from the initial to the final position of the body. It is not always eqaul to path length. It can be zero and -ve also.

  • Question 7
    1 / -0

    Given vectors a, b, c, d and a + b + c + d = 0, which of the following statements not correct?

    Solution

    In order to make vectors a + b + c + d = 0, it is not necessary to have all the four given vectors to be null vectors. There are many other combinations which can give the sum zero.

    (b) Correct
    a + b + c + d = 0
    a + c = – (b + d)
    Taking modulus on both the sides, we get:
    | a + c | = | –(b + d)| = | b + d |
    Hence, the magnitude of (a + c) is the same as the magnitude of (b + d).

    (c) Correct
    a + b + c + d = 0
    a = – (b + c + d)
    Taking modulus both sides, we get:
    | a | = | b + c + d |
    | a |  ≤  | a | + | b | + | c | .....  (i)

    Equation (i) shows that the magnitude of a is equal to or less than the sum of the magnitudes of b, c, and d.
    Hence, the magnitude of vector a can never be greater than the sum of the magnitudes of b, c, and d.

    (d) Correct
    For a + b + c + d = 0
    a + (b + c) + d = 0
    The resultant sum of the three vectors a, (b + c), and d can be zero only if (b + c) lie in a plane containing a and d, assuming that these three vectors are represented by the three sides of a triangle.

    If a and d are collinear, then it implies that the vector (b + c) is in the line of a and d. This implication holds only then the vector sum of all the vectors will be zero.

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