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Work Energy and Power Test - 56

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Work Energy and Power Test - 56
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  • Question 1
    1 / -0
    A particle moves along the x-axis from x=0 to x=5 m under the influence of a force given by $$F=\left( { 7-2x+3x }^{ 2 } \right) N.$$ The work done in the process is
    Solution

  • Question 2
    1 / -0
    A force $$F_1$$ on a body of 2 kg produces an acceleration of $$2.5 m/m^2$$ and other force $$F_2$$ acting on another body of mass 5 kg produces an acceleration of $$2 m/s^2$$. The ratio of $$F_2/F_1$$ is
    Solution
    Given,
    $$m_1=2kg$$
    $$a_1=2.5m/s^2$$
    $$m_2=5kg$$
    $$a_2=2m/s^2$$

    Ratio, $$\dfrac{F_2}{F_1}=\dfrac{m_2a_2}{m_1a_1}$$

    $$\dfrac{F_2}{F_1}=\dfrac{5\times 2}{2\times 2.5}=2$$
    The correct option is A.
  • Question 3
    1 / -0
    A force $$\vec { F } = 2 x \hat { i } + 3 y ^ { 2 } \hat { j } \mathrm { N }$$ where x and y are in meter, acts upon a particle. Find work done (in J) by this force in displacing the particle from (1 m, 2 m, 5 m) to (2 m, 3 m, 2 m).
    Solution

  • Question 4
    1 / -0
    The amount of work done in stretching a wire by 10N force can cause an elongation of $$2×{ 10 }^{ -2 }m$$ will be 
    Solution

  • Question 5
    1 / -0
    Velocity-time graph of a particle of mass 2 kg moving in a straight line is as shown in figure. Work done by all the forces on the particle during the motion is:

    Solution

  • Question 6
    1 / -0
    A particle is displaced from a position $$(2\hat { i } -\hat { j } +\hat { k } )$$ metre to another position $$(3\hat { i } +2\hat { j } -2\hat { k } )$$ meter under the action of force $$(2\hat { i } +\hat { j } -\hat { k } )$$ N. Work done by the force is:
    Solution

  • Question 7
    1 / -0
    A balloon with its contents weighing 160 N is moving down with an acceleration of g/2 $${ ms }^{ -2 }$$ the mass to be removed from it so that the balloon moves up with an acceleration of g/3$${ ms }^{ -2 }$$ is 
    Solution

  • Question 8
    1 / -0
    In the figure, at the free end of the light string, a force $$F$$ is applied to keep the suspended mass of $$18 $$\mathrm { kg }$$ at rest. Assuming


    Solution
    $$3T=180$$
    or, $$T=60 N$$
    Now, $$F=T=60 N$$
    Therefore ,total force on ceiling is $$4T=240 N$$
    Hence, Option $$A$$ is correct.
  • Question 9
    1 / -0
    The breaking strength of a string is 55 kg wt. The maximum permissible speed of a stone of mass 5 kg which revolved in a vertical circle of radius 4 m with the help of is the string is g=10 $$ {s}^{2} $$.
  • Question 10
    1 / -0
    A force of $$ \left(4 x^{2}+3 x\right)  $$ N acts on a particle which displaces it from $$  x=2 m  $$ to $$  x=3 \mathrm{m}  $$.
    The work done by the force is
    Solution

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