Self Studies

Work Energy and Power Test - 59

Result Self Studies

Work Energy and Power Test - 59
  • Score

    -

    out of -
  • Rank

    -

    out of -
TIME Taken - -
Self Studies

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Self Studies Self Studies
Weekly Quiz Competition
  • Question 1
    1 / -0
    How much height must an object of mass $$5kg$$ be lifted to have potential energy $$5000J$$ ?$$[g=10 m/s^2]$$
    Solution
    Gravitation potential energy is given by $$P.E = mgh $$
    Given:
    Mass $$m=5 \ kg$$
    $$g=10 \ m/s^2$$
    $$5000 = 5 \times 10 \times h $$
    $$ \implies h = 100 m$$ 
  • Question 2
    1 / -0

    Directions For Questions

    A block of mass $$2\ m$$ collides elastically with a mass $$m$$ kept at rest. Friction exists between the block $$B$$ and surface with coefficient $$\mu =0.3$$, whereas no friction exists between block $$A$$ and the surface.

    ...view full instructions

    The block will again collide after time:
    Solution

  • Question 3
    1 / -0

    Directions For Questions

    A block of mass $$2\ m$$ collides elastically with a mass $$m$$ kept at rest. Friction exists between the block $$B$$ and surface with coefficient $$\mu =0.3$$, whereas no friction exists between block $$A$$ and the surface.

    ...view full instructions

    How many collision are possible between the blocks?
    Solution
    As the distance keeps on decreasing  and there will be a deceleration in the blocks .
     
    In further results,   collision increases frequently many times  and slowly come in contact.
     
    So infinite collision possible between the blocks.
  • Question 4
    1 / -0
    A car is accelerated on a levelled road and attains a speed of $$5$$ times its initial speed. In this process , the kinetic energy of the car:
    Solution

    Lets initial velocity of car is $$v$$, final velocity of this car will be $$5\ v$$

    $$K.E  = \dfrac{1}{2}$$ $$ mv ^{2}$$

    $$\therefore \ K.E\propto v^2$$

    $$K.E_{f}=K.E_i \left(\dfrac{v_f}{v_i}\right)^2$$   where   $$f$$ stand for final and $$i$$ for initial.

    $$K.E_{f}=K.E_i \left(\dfrac{5v}{v}\right)^2=25\ K.E_i$$

    So, when the speed increases to 5 times of its initial velocity, the kinetic energy will become 25 times.

    The correct answer is d) becomes $$25$$ times that of initial kinetic energy
  • Question 5
    1 / -0
    When a stone of mass 'm' falls through a vertical height 'd', the decrease in the gravitational energy is:
    Solution
    Potential energy stored in a body of mass m and at height 'd' will be given by $$m \times g \times d$$
    This gravitational potential energy keeps on decreasing with the decrease in height of stone, and when the stone falls completely, this potential energy is lost . So when object loses height $$d $$ the corresponding loss in potential Energy is $$= mgd$$
  • Question 6
    1 / -0
    Potential energy of a person is minimum when:
    Solution
    Potential energy of a body is defined as energy of a body due to its position in gravitational field. 
    In general,  
    Potential energy $$= M \times g \times h$$         where: h is the height above ground.
    If the person will be lying on ground then it will have minimum height above the ground therefore potential energy of the person will also be minimum.
  • Question 7
    1 / -0
    A car is accelerated on a leveled road and attains a velocity $$4$$ times its initial velocity. In this process, the potential energy of the car:
    Solution
    Potential energy depends on the height at which the object is situated. Where potential energy is measured by the product of the mass of the object, gravity, and height. In this case, there is no change in height of the object. Hence, there is no change in its potential energy.
  • Question 8
    1 / -0
    An object of mass $$5 \,kg$$ falls from a height of $$5 \,m$$ above the ground. The loss of potential energy of the mass is:
    Solution
    Given,
    $$Mass = 5 \,kg$$
    $$Height = 5 \,m$$
    Let $$g = 10 \,ms^{-2}$$
    Potential energy stored in a body of mass m and height h will be given by
    $$= m \times g \times h$$
    $$= 5 \,kg \times 10 \,ms^{-2} \times 5 \,m$$
    $$= 250 \,J$$
    When the mass falls completely, same potential energy is lost $$= 250 \,J$$
  • Question 9
    1 / -0
    When a boy triples his speed, his kinetic energy becomes 
    Solution

    Given that, speed of particle is becoming 3 times of its initial value while moving. ie $$v'=3v$$

    As we know            $$K.E = \dfrac{1}{2}$$ $$ mv ^{2}$$ ..........(1)

    After velocity tripled     $$K.E' = \dfrac{1}{2}$$ $$ m(3v) ^{2}=\dfrac92mv^2$$...........(2)

    From equation 1 and 2

     $$K.E' = 9 \times K.E$$ 

    When a boy tripled his speed, his kinetic energy will becomes nine times.
  • Question 10
    1 / -0
    A position dependent force $$ F = 7 - 2x + 3x^2 $$ newton acts on a small body of mass $$2 $$ kg displace it from $$ x = 0$$ to $$ x = 5 m $$ the work done in joules is 
    Solution
    It is known that $$W=\int Fdx$$

    $$ W = \int^5_0 Fdx = \int^5_0 ( 7- 2x +3x^2) dx$$

    $$W  = [ 7x - x^2 + x^3]^5_0 $$

    $$ W= 35 -25 + 125 = 135 J $$
Self Studies
User
Question Analysis
  • Correct -

  • Wrong -

  • Skipped -

My Perfomance
  • Score

    -

    out of -
  • Rank

    -

    out of -
Re-Attempt Weekly Quiz Competition
Selfstudy
Selfstudy
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now