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Gravitation Test - 68

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Gravitation Test - 68
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  • Question 1
    1 / -0
    The gravitational potential at the centre of a square of side a when four point masses m each are kept at its vertices will be 
    Solution
    $$\begin{array}{l} AO=\dfrac { { \sqrt { 2 } a } }{ 2 } =\dfrac { a }{ { \sqrt { 2 }  } }  \\ V=\dfrac { { -Gm } }{ r }  \\ { V_{ net } }=\dfrac { { -4Gm } }{ r } =\dfrac { { -4Gm } }{ { \dfrac { a }{ { \sqrt { 2 }  } }  } } =\dfrac { { -4\sqrt { 2 } Gm } }{ a }  \end{array}$$.
    $$\therefore$$ Option $$B$$ is correct.

  • Question 2
    1 / -0
    Two astronauts are floating in gravitational free space after having lost contact with their spaceship. The two will.
    Solution

  • Question 3
    1 / -0
    The gravitational force between two point masses $${ m }_{ 1 }$$ and $${ m }_{ 2}$$ at separation r is given by 
    $$F=k\dfrac { { m }_{ 1 }{ m }_{ 2 } }{ { r }^{ 2 } } .$$
    The constant k depends on :
    Solution

  • Question 4
    1 / -0
    How much percentage change in acceleration due gravity on an object occurs if object is initially at '2R' distance above the surface of the earth and falls through 'R' distance? (Here, R is the radius of earth)
    Solution

  • Question 5
    1 / -0
    The radius of the Earth shrinks by $$1$$%, its mass remaining the same. The percentage change in the value of $$g$$ on surface of earth is 
    Solution

  • Question 6
    1 / -0
    IF the acceleration due to gravity, $$g$$, is 10m/$${ s }^{ 2 }$$ at the surface of the earth (radius $$6400 km$$ ), then at a height of $$1600 m$$ the value of $$g$$ will be (in m/$${ s }^{ 2 }$$)
    Solution

  • Question 7
    1 / -0
    If the earth were to cases rotating about its own axis. The increase in the value of g in CGS system at a place of latitude of $${ 45 }^{ o }$$ will be
    Solution

  • Question 8
    1 / -0
    A bird weighing $$1kg$$ is sitting on the base of cage weighing $$1.5kg$$. The bird strarts flying inside the cage the weight of the bird cage assembly will now be:
    Solution

  • Question 9
    1 / -0
    If the radius of the earth is 6400 km and g = 10 $${ m/s }^{ 2 }$$, the escape velocity from the earth is 
    Solution

  • Question 10
    1 / -0
    If a ball is projected with a velocity equal to 1/4th of the escape velocity from the surface of the earth. the height it will attain is ___________ [ R : Radius of Earth]
    Solution
    from newton's eqn. of motion
    $$h = \dfrac{v^2}{2g}$$
    $$v = v_{esc} = \sqrt{2gR}$$
    as per question
    $$h = \dfrac{\left(\dfrac{1}{4}\sqrt{2gR}\right)^2}{2g} = \dfrac{2gR}{32g}$$
    $$h = \dfrac{R}{16}$$
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