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Gravitation Test - 82

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Gravitation Test - 82
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  • Question 1
    1 / -0
    The ratio of acceleration due to gravity at a depth h below the surface of earth and at a height h above the surface of earth for h < < R (where R is radius of earth)
    Solution

  • Question 2
    1 / -0
    The linear velocity of a body at the equator of the earth will be about ((Radius of earth at equator =6.4×106m) =6.4 \times 10^{6} \mathrm{m} )
    Solution

  • Question 3
    1 / -0
    The acceleration due to gravity becomes (g2)(\frac{g}{2})  where g=acceleration due to gravity on the surface of the earth at a height equal to
  • Question 4
    1 / -0
    Who among the following did first give the experimental value of GG?
    Solution

  • Question 5
    1 / -0
    At what height from the surface of earth the gravitation potential and the value of g are 5.4×107J/kg -5.4 \times 10^7 J/kg and 6.0m/s2 6.0 m/s^2 respectively?
    take the radius of earth as 6400 km:
    Solution

  • Question 6
    1 / -0
    To double the orbital speed V and halve the angular velocity ω\omega , The centripetal acceleration of a revolving body:
    Solution

  • Question 7
    1 / -0
    The height above the surface of the earth where acceleration due to gravity is 1/641/64 of its value at surface of the earth is approximately
  • Question 8
    1 / -0
    If the radius of a planet shrinks by 2% while its mass remaining the unchanged, the acceleration due to gravity on the planet's surface would 
    Solution

  • Question 9
    1 / -0
    The ratio of acceleration due to gravity at a depth hh below the surface of earth and at a height hh above the earth surface of earth (h << radius of earth ) is 
    Solution

  • Question 10
    1 / -0
    The value of  gg  will be  1%1\%  of its value at the surface of earth at a height of  (Re=6400km).\left( R _ { e } = 6400 k m \right).
    Solution

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