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Mechanical Properties of Solids Test - 5

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Mechanical Properties of Solids Test - 5
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    A hydraulic press contains 0.25 3 (250 L) of oil. Find the decrease in the volume of the oil when it is subjected to a pressure increase Δp = 1.6 × 107 Pa(about 160 atm or 2300 psi). The bulk modulus of the oil is B = 5.0 × 109 Pa

    Solution

    ΔV=−V0Δp/B=−(0.25 m3)x(1.6×107 Pa)/5.0×109 Pa

     ∆V=-V0∆p/B=-(0.25 m3x1.6×107 Pa)/5.0×109 Pa 

    =−8.0×10−4 m3=− 0.80L=-8.0×10-4 m3=- 0.80L

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