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Mechanical Properties of Solids Test - 82

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Mechanical Properties of Solids Test - 82
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  • Question 1
    1 / -0
    A uniform metal wire ring of mass per unit length $$\lambda$$ and radius $$r$$ has cross sectional area $$S$$.
    If $$Y$$ is Young's in modulus of elasticity and it is rotated with and angular velocity $$\omega$$ about it own axis then approximate fractional change in radius is 
  • Question 2
    1 / -0
    A steel rod of cross sectional area $$1 m^2$$ is acted upon by forces shown in the fig. Determine the total elongation of the bar. ($$Y = 2.0 \times 10^{11} N/m^2$$)

    Solution

  • Question 3
    1 / -0
    What force should be applied to the ends of steel rod of a cross sectional area  $$10 { cm } ^ { 2 }$$  to prevent it from elongation when heated from  $$273 { K }$$  to  $$303 { K }$$  ? ( $$\alpha$$  of steel  $$10^{ { -5 } }\quad ^{ 0 }{ { C }^{ -1 } },Y=2\times 10^{ { 11 } }{ Nm }^{ { -2 } }$$ )
    Solution

  • Question 4
    1 / -0
    In the young's double slit experiments, the intensities at two points $$ P_1 $$ and $$ P_2 $$ on the screen are respectively.$$ I_1 $$ and $$ I_2 $$. If $$ P_1 $$ is located at the centre of a bright fringe and $$ P_2 $$ is located at a distance equal to a quarter of fringe width from $$ P_1$$, then $$ \frac {I_1}{I_2} $$ is
    Solution
    $$\begin{array}{l}\text { Given, } \\\text { } P_{1} \text { and } P_{2} \text { are two points on screen and } \\\text I_{ 1 } { and } I_{2}\text { are their intensities respectively. } \\\text {} P_{2} \text { is located at quarter of fringe width }\end{array}$$
    $$Y_{p_{2}}=\frac{\beta}{4}, \beta=\text { fringe width }$$
    $$y_{p_{2}}=\frac{\lambda D}{4 d}$$
    $$\begin{array}{c}\text { and } p_{1} \text { is located at centre of bright fringe } \\\qquad y_{p_{1}}=0\end{array}$$
    $$\begin{array}{l}\text { now, } \\\qquad\begin{aligned}\frac{Y_{2} d}{D} &=\frac{\lambda}{4} \\\Delta x_{p_{2}} &=\frac{\lambda}{4}\end{aligned}\end{array}$$
    $$\begin{aligned}\text { Now, }\\\text { phase difference }(\phi) &=\frac{2 \pi}{\lambda}\times\text { Path difterence } \\&=\frac{2 \pi}{\lambda} \times \frac{\lambda}{4}\\\phi_{P_{2}} &=\frac{\pi}{2}\end{aligned}$$
    $$\text { So, }\begin{aligned}I_{2} &=4 I_{0} \cos ^{2}\left(\frac{\phi}{2}\right) \\&=4 I_{0} \cos ^{2}(45) \\I_{2} &=\frac{4 I_{0}}{2}\end{aligned}$$
    $$\text { Now for } P_{1} \text { as it lies at centre of fringe }$$
    $$\begin{aligned} & \phi_{p_{1}}=0 \\ I_{1} &=4 I_{0} \cos ^{2}(0) \\ I_{1} &=4 I_{0} \\ \text { Now, } & \frac{I_{1}}{I_{2}}=\frac{4 I_{0}}{2 I_{0}}=2 \end{aligned}$$

  • Question 5
    1 / -0
    If uniform rod of length  $$5 { m },$$  area of cross-section  $$50{ cm }^{ { 2 } }$$  and Young's modulus  $$4 \times 10 ^ { 9 }  { Pa }$$  is lying at rest under the action of forces as shown, then the total extension in the rod is

    Solution

  • Question 6
    1 / -0
    In the question $$22$$, when is the tensile stress maximum ?
  • Question 7
    1 / -0
    A uniform steel rod of length 1m and area of cross section 20 $$ c{ m }^{2  } $$ is hanging from a fixed support. Find the increase in the length of the rod.
    $$ ({  Y}_{ steel }=2.0\times 1{0  }^{ 11 }N{m  }^{ -2 }, {P  }_{ steel }= 7.85\times 1{0  }^{ 3 }kg{m  }^{-3  }) $$
    Solution

  • Question 8
    1 / -0
    A uniform wire fixed at its upper end hangs vertically and supports a weight at its lower end. If its radius is r, length is L and the Young's modulus for the material of the wire is E then extension produced in the wire is
    Solution

  • Question 9
    1 / -0
    A steel wire of length 4 m and diameter 5 mm is stretched by 5 kgwt. The increase in its length , if the Young's modulus of steel wire is $$2.4 \times { 10 }^{ 12 } dyne/{ cm }^{ 2 }$$. is
    Solution

  • Question 10
    1 / -0
    A body of mass 10 kg is attached to a 0.3 m long wire of cross area $${ 10 }^{ 6 }$$ $${ m }^{ 2 }$$ Breaking steers of the wire if $$4.8\times { 10 }^{ 7 }$$ What is the maximum angular velocity with which it can be rotated in a horizontal circle? 
    Solution

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