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Molecular Basis of Inheritance Test - 68

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Molecular Basis of Inheritance Test - 68
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  • Question 1
    1 / -0
    The coding segment of DNA contains CAC. Which amino acid is picked up during translation?
  • Question 2
    1 / -0
    Removal of introns and joining the exons in a defined order in a transcription unit is
  • Question 3
    1 / -0
    Which is correct
  • Question 4
    1 / -0
    Which defines the position and presence of template and coding strands in transcription unit
    Solution
    It is a DNA sequence that provides binding site for RNA polymerase and it is the presence of promoter in a transcription unit that also defines the template and coding strands.
    Option A is correct answer.
  • Question 5
    1 / -0
    Which one of the following acts as a catalyst in a bacterial cell
  • Question 6
    1 / -0
    Which codon does not have tRNA?
    Solution
    A. Start codon is AUG. Since AUG also codes for methionine, it has a tRNA molecule carrying methionine in eukaryotes and formylated methionine in prokaryotes.
    B. There are three stop codons UAA, UAG, UGA. These do not code for any amino acid. Hence, they do not have tRNA molecules.
    C. AUG codes for methionine. Hence, it has tRNA molecule carrying methionine.
    D. GGG codes for glycine and has a tRNA molecule carrying glycine.
    E. UUU codes for phenylalanine and has a tRNA molecule carrying phenylalanine.
    So, the correct answer is 'Stop codon'.
  • Question 7
    1 / -0
    Hargobind Khorana contributed to genetic engineering by synthesising 
    Solution
    Hargobind Khorana was the pioneer in DNA technology who discovered codons or three base sequences in a DNA  and was the first to synthesize an artificial gene.
    So the correct answer is "Artificial gene".
  • Question 8
    1 / -0
    Select the incorrect statement.
    a. Six codons do not code for any amino acid.
    b. Codon reading of mRNA is contiguous.
    c. Three codons function as stop codons.
    d. Initiator codon AUG codes for methionine.
    Solution
    A. a alone is incorrect
    Solution : Codon reading of mRNA is contiguous and continuous. Three codons code for stopping the protein synthesis which are UAA, UAG and UGA. Initiator codon (AUG) codes for methionine.
    So the correct answer is "a alone is incorrect".
  • Question 9
    1 / -0
    Which is not part of transcription unit
  • Question 10
    1 / -0
    Choose the wrong statement regarding the observation drawn from Human Genome Project
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