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Solid State Test - 19

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Solid State Test - 19
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  • Question 1
    1 / -0
    Which of the following patterns has void fraction of $$0.26$$?
    Solution
    ABCABCABC... patterns has void fraction of 0.26. It corresponds to ccp (cubic close packing) or fcc (face centered cubic) unit cell.  Occupied space is 74% and empty space is 26%.
  • Question 2
    1 / -0
    Which of the following about the above structure is incorrect?

    Solution
    In this type of structure, the coordination number is $$4:4$$ i.e. each $$X$$ atom is surrounded by 4 $$Y$$ atoms and each $$Y$$ atom is surrounded by 4 $$X$$ atoms.
    So, option B is not correct.

  • Question 3
    1 / -0
    In an ionic compound $$A^{+}X^{-}$$, the radii of $$A^{+}$$ and $$X^{-}$$ ions are 1.0 pm and 2.0pm, respectively. The volume of the unit cell of the crystal AX will be :
  • Question 4
    1 / -0
    The radius of a calcium ion is 94 pm and of the oxide, the ion is 146 pm. The possible crystal structure of calcium oxide will be:- 
    Solution

  • Question 5
    1 / -0
    In case of cubic system, the number of types of space lattices?
    Solution
    There are 14 space lattices are possible in a crystal.
  • Question 6
    1 / -0
    How many unit cell of $$NaCl$$ are present in $$7.02\ gm$$ of $$NaCl?$$
    Solution

  • Question 7
    1 / -0
    What is the number of ions per $$cc$$ in the crystal of $$NaCl$$ at normal temperature?
    Solution
    Number of ions per cc in crystal of $$NaCl$$ at normal temperature is $${10}^{22}$$ ions
  • Question 8
    1 / -0
    Which of the following have maximum lattice energy :
    Solution
    $$L.E$$      $$\alpha$$    $$|Z^+||Z^-|$$
                  $$\alpha$$    $$\dfrac{1}{Size}$$ of ion
    So $$LiF$$ should have
    Highest $$L.E$$
  • Question 9
    1 / -0
    A metallic element crystallizes into a lattice containing a  sequence of layers of AB AB AB....Any packing of spheres leaves out voids in the lattice. The empty space in percentage by volume in this lattice is: 
    Solution
    AB AB type close packing is actually Hexagonal close packing. In HCP, the space occupied by atoms is 74% and empty space due to voids is 26%.
  • Question 10
    1 / -0
    In $$CaF_2$$ lattice coordination number of $$Ca^{+2}$$ & $$F^-$$ is :
    Solution
    $$Ca^{+2}$$ occupy at $$FCC$$ lattice site and $$F-$$ occupy at tetrahedral void so $$C.N.$$ of $$Ca^{+2} = 8$$ and $$F- C.N. = 4$$
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