Solid State Tes...

Sodium crystallizes in the cubic lattice and the edge of the unit cell is $$ 430 pm$$. Calculate no of atoms in the unit cell.
[atomic mass of sodium = $$ 23.0$$ amu.
density of sodium = $$ 0.9623$$ g $$cm^{-3}$$.]

If the ratio of the coordination number of $$A$$ to that of $$B$$ is $$x:y$$, then the ratio of number of atoms of $$A$$ to that of $$B $$ in the unit cell is:

Silver crystallizes in fcc structure with edge length of unit cell, $$408.7pm$$. Hence density of silver is $$(Ag = 108\ g\ mol^{-1})$$

In chromium chloride $$(CrCl_3)$$, $$Cl^-$$ ions have cubic close packed arrangement and $$Cr^{3+}$$ ions are present in the octahedral holes. The fraction of the total number of holes occupied is:

Copper crystallizes in fcc structure and the edge length of the unit cell is $$3.61A^o$$. Hence the density of copper is:
(atomic mass of $$Cu = 63.5\ g \ mol^{-1}$$)

The atomic radius of metal crystallizing in fcc structure true is $$1.25A^o$$. Hence the volume occupied by atoms in cell crystal is:

The crystal system possess by $${K}_{2}{Cr}_{2}{O}_{7}$$ is:

A metal $$M$$ is crystallised in $$F.C.C$$ lattice. The number of unit cells in it having $$2.4\times 10^{24}$$ atoms are:

The rank of atoms in the hexagonal until cell is:

In fcc, the neighbouring number of atoms for any lattice points is: